d. The ultimate frictional resistance Q₁. [Use Eqs. (12.42) through (12.44), and take K = 1.4 and 8' = 0.60'.] e. The allowable load of the pile (use FS = 4). 3 m 3 m 15 m 381 mm Groundwater table 15.7 kN/m³ Y o' = 32° c' = 0 Ysat 18.2 kN/m³ $' = 32° c' = 0 Ysat = 19.2 kN/m³ $' = 40° c' = 0
d. The ultimate frictional resistance Q₁. [Use Eqs. (12.42) through (12.44), and take K = 1.4 and 8' = 0.60'.] e. The allowable load of the pile (use FS = 4). 3 m 3 m 15 m 381 mm Groundwater table 15.7 kN/m³ Y o' = 32° c' = 0 Ysat 18.2 kN/m³ $' = 32° c' = 0 Ysat = 19.2 kN/m³ $' = 40° c' = 0
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
Related questions
Question
d and e only
![12.7 A driven closed-ended pile, circular in cross section, is
shown in Figure P12.7. Calculate the following.
a. The ultimate point load using Meyerhof's procedure.
b. The ultimate point load using Vesic's procedure. Take
Irr = 50.
c. An approximate ultimate point load on the basis of parts
(a) and (b).
d. The ultimate frictional resistance Q₁. [Use Eqs. (12.42)
through (12.44), and take K = 1.4 and 8' = 0.60'.]
e. The allowable load of the pile (use FS = 4).
3 m
3 m
15 m
381 mm
FIGURE P12.7
Groundwater
table
=
Y
$' = 32°
c' = 0
15.7 kN/m³
=
Ysat 18.2 kN/m³
$' = 32°
c' =0
Ysat
19.2 kN/m³
$' = 40°
c' = 0](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8ab2a08c-1a87-4c82-9da5-56b391a62f8c%2F7ded4b91-6e2e-47ff-bef5-24dfb101017f%2Fixri1o_processed.png&w=3840&q=75)
Transcribed Image Text:12.7 A driven closed-ended pile, circular in cross section, is
shown in Figure P12.7. Calculate the following.
a. The ultimate point load using Meyerhof's procedure.
b. The ultimate point load using Vesic's procedure. Take
Irr = 50.
c. An approximate ultimate point load on the basis of parts
(a) and (b).
d. The ultimate frictional resistance Q₁. [Use Eqs. (12.42)
through (12.44), and take K = 1.4 and 8' = 0.60'.]
e. The allowable load of the pile (use FS = 4).
3 m
3 m
15 m
381 mm
FIGURE P12.7
Groundwater
table
=
Y
$' = 32°
c' = 0
15.7 kN/m³
=
Ysat 18.2 kN/m³
$' = 32°
c' =0
Ysat
19.2 kN/m³
$' = 40°
c' = 0
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