ouTube Maps 4 6 5 CH2OH ОН ОН ОН 3 The Haworth projection of D-mannose is shown. 1 Question 10 of 37 2 ОН Which anomer is depicted? A) alpha B) beta C) gamma D) delta +

Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter22: Organic And Biological Molecules
Section: Chapter Questions
Problem 165CP
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### Educational Content on D-Mannose Haworth Projection

#### Question 10 of 37

**Topic:** Carbohydrate Chemistry

**Question:** The Haworth projection of D-mannose is shown. Which anomer is depicted?

![Haworth projection of D-mannose](image-link-not-available)

1. **Explanation of the Diagram:**
    - The diagram illustrates the Haworth projection of D-mannose. 
    - The cyclic structure consists of a six-membered ring (a pyranose form). This is indicated by the carbons 1 through 6.
      
       **Structure Details:**
    - **Carbon 1 (C1):** This is the anomeric carbon in the ring structure on which the OH group can be either above (beta) or below (alpha) the plane of the ring.
    - **Carbon 2 (C2), Carbon 3 (C3), and Carbon 4 (C4):** Each of these carbons has an OH group attached.
    - **Carbon 5 (C5):** This carbon atom is bonded to a CH2OH group.
    - **Carbon 6 (C6):** Located outside the ring, attached to the CH2OH group.

2. **Question Options:**
    - A) alpha
    - B) beta
    - C) gamma
    - D) delta
   
3. **Identifying the Anomer:**
    - The configuration around the anomeric carbon (C1) in the Haworth projection specifies the anomer.
    - The structure shown depicts the OH group on C1 below the plane of the ring, indicating the alpha (α) anomer of D-mannose.

**Answer:** A) alpha

This educational information helps students understand the structural representation of carbohydrates and how to determine the specific anomer of a sugar from its Haworth projection.
Transcribed Image Text:### Educational Content on D-Mannose Haworth Projection #### Question 10 of 37 **Topic:** Carbohydrate Chemistry **Question:** The Haworth projection of D-mannose is shown. Which anomer is depicted? ![Haworth projection of D-mannose](image-link-not-available) 1. **Explanation of the Diagram:** - The diagram illustrates the Haworth projection of D-mannose. - The cyclic structure consists of a six-membered ring (a pyranose form). This is indicated by the carbons 1 through 6. **Structure Details:** - **Carbon 1 (C1):** This is the anomeric carbon in the ring structure on which the OH group can be either above (beta) or below (alpha) the plane of the ring. - **Carbon 2 (C2), Carbon 3 (C3), and Carbon 4 (C4):** Each of these carbons has an OH group attached. - **Carbon 5 (C5):** This carbon atom is bonded to a CH2OH group. - **Carbon 6 (C6):** Located outside the ring, attached to the CH2OH group. 2. **Question Options:** - A) alpha - B) beta - C) gamma - D) delta 3. **Identifying the Anomer:** - The configuration around the anomeric carbon (C1) in the Haworth projection specifies the anomer. - The structure shown depicts the OH group on C1 below the plane of the ring, indicating the alpha (α) anomer of D-mannose. **Answer:** A) alpha This educational information helps students understand the structural representation of carbohydrates and how to determine the specific anomer of a sugar from its Haworth projection.
### Educational Website: Organic Chemistry Exam Preparation

#### Question 7 of 37

**Which carbon is the anomeric carbon in the structure shown here?**

Diagram: 

The diagram represents a cyclical carbohydrate molecule, specifically a glucose molecule in its ring form. There are several carbon atoms labeled as A, B, C, D, and E, along with various hydrogen (H), hydroxyl (OH), and CH2OH groups attached to the carbon atoms.

- **A**: This carbon is attached to a CH2OH group.
- **B**: This carbon is attached to a Hydrogen (H) atom and a hydroxyl (OH) group.
- **C**: This carbon is attached to a Hydrogen (H) atom and a hydroxyl (OH) group.
- **D**: This carbon is attached to a Hydrogen (H) atom and the ring oxygen.
- **E**: This carbon is attached to a Hydrogen (H) atom and a hydroxyl (OH) group, and it is connected to the ring oxygen, making it the anomeric carbon in this structure.

Options provided for the question:

- A) A
- B) B
- C) C
- D) D
- E) E

In this structure, the anomeric carbon is carbon **E**, which is the carbon that was originally the carbonyl carbon in the straight-chain form of the glucose molecule. In the ring form, it is the carbon connected to two oxygen atoms - one in the ring and one in a hydroxyl group.

**Correct Answer: E) E**

By understanding this, students can identify the anomeric carbon in carbohydrate molecules, a fundamental concept in organic chemistry.

To learn more about identifying anomeric carbons and their significance in biochemistry, please refer to our detailed guide on carbohydrate chemistry.
Transcribed Image Text:### Educational Website: Organic Chemistry Exam Preparation #### Question 7 of 37 **Which carbon is the anomeric carbon in the structure shown here?** Diagram: The diagram represents a cyclical carbohydrate molecule, specifically a glucose molecule in its ring form. There are several carbon atoms labeled as A, B, C, D, and E, along with various hydrogen (H), hydroxyl (OH), and CH2OH groups attached to the carbon atoms. - **A**: This carbon is attached to a CH2OH group. - **B**: This carbon is attached to a Hydrogen (H) atom and a hydroxyl (OH) group. - **C**: This carbon is attached to a Hydrogen (H) atom and a hydroxyl (OH) group. - **D**: This carbon is attached to a Hydrogen (H) atom and the ring oxygen. - **E**: This carbon is attached to a Hydrogen (H) atom and a hydroxyl (OH) group, and it is connected to the ring oxygen, making it the anomeric carbon in this structure. Options provided for the question: - A) A - B) B - C) C - D) D - E) E In this structure, the anomeric carbon is carbon **E**, which is the carbon that was originally the carbonyl carbon in the straight-chain form of the glucose molecule. In the ring form, it is the carbon connected to two oxygen atoms - one in the ring and one in a hydroxyl group. **Correct Answer: E) E** By understanding this, students can identify the anomeric carbon in carbohydrate molecules, a fundamental concept in organic chemistry. To learn more about identifying anomeric carbons and their significance in biochemistry, please refer to our detailed guide on carbohydrate chemistry.
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