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Question 9 of 23
A 35.0 mL solution of Ba(OH)2 is neutralized with 29.8 mL of 0.350 M
HNO3. What is the concentration of the original Ba(OH)2 solution?
Transcribed Image Text:ortal https://app.101edu.co Handshake 121 D2L Ch. 1 Introduction -... Aktiv Chemistry Connect-Bio Google Docs Quizlet #20 hybrid <-2022 Subaru WRX A Question 9 of 23 A 35.0 mL solution of Ba(OH)2 is neutralized with 29.8 mL of 0.350 M HNO3. What is the concentration of the original Ba(OH)2 solution?
Expert Solution
Step 1

   

    • The neutralization reaction is :- 

    Ba(OH)2 + 2 HNO---> Ba(NO3)2 + 2 H2

    Given, 

         A 35.0 mL solution of Ba(OH)2 is neutralized with 29.8 mL of 0.350 M HNO3 .

 Now ,  from the above reaction  the mole fraction between Ba(OH)2 and HNO3 is 1:2 .

 •   Number of moles of HNO 

        = (0.0298 L * 0.350 mol.L-1

     = 0.01043  Moles.

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