By titration, it is found that 70.9 mL of 0.160 M NaOH(aq) is needed to neutralize 25.0 mL of HCl(aq). Calculate the concentration of the HCl solution. [HC1] = M

Q: Calculate the molar mass of the unknown acid. Be sure your answer has the correct number of…

A: We calculate normality of acid and base then use this formula N1V1 = N2V2

Q: By titration, it is found that 24.7 mL of 0.184 M NaOH(aq) is needed to neutralize 25.0 mL of…

A: The reaction of HCl with NaOH is a neutralization reaction that forms NaCl and water as the…

Q: By titration, it is found that 56.9 mL of 0.142 M NaOH(aq) is needed to neutralize 25.0 mL of…

A: Number of moles of solute present in 1 liter of solution is known as molarity of the solution.

Q: A strong acid-strong base titration was performed as follows: 10.00 mL of 0.10M HCl were collected…

A: Molarity of HCl = 0.1 M Volume of HCl = 10 mL Molarity of NaOH = 0.1 M Volume of NaOH = 10 mL Moles…

Q: By titration, it is found that 51.5 mL of 0.183 M NaOH(aq) is needed to neutralize 25.0 mL of…

A:

Q: By titration, it is found that 62.5 mL of 0.176 M NaOH(aq) is needed to neutralize 25.0 mL of…

A: Step 1:To find the concentration of the HCl solution, we can use the equation for neutralization…

Q: By titration, it is found that 73.9 mL of 0.190 M NAOH(aq) is needed to neutralize 25.0 mL of…

A: Given :- concentration of NaOH = 0.190 M             Volume of NaOH solution = 73.9 mL…

Q: By titration, it is found that 77.3 mL of 0.122 M NaOH(aq) is needed to neutralize 25.0 mL of…

A: Answer: In neutralization reaction, hydroxide ion of base reacts with hydrogen ion of acid and…

Q: By titration, it is found that 13.5 mL of 0.112 M NaOH(aq) is needed to neutralize 25.0 mL of…

A: Since the reaction taking place is given by  NaOH + HCl ----> NaCl + H2O Hence we can say that 1…

Q: By titration, it is found that 58.5 mL of 0.177 M NaOH(aq) is needed to neutralize 25.0 mL of…

A:

Q: By titration, it is found that 24.5 mL of 0.173 M NaOH(aq) is needed to neutralize 25.0 mL of…

A: The question is based on the concept of titration. We have to calculate concentration of…

Q: Titration of a 25.00 mL sample of acid rain required 12.4 mL of 0.009879 M NaOH to reach the end…

A: Volume of sulphuric acid,V1 = 25.00mL Volume of NaOH,V2 = 12.4mL Concentration of NaOH,M2 =…

Q: By titration, it is found that 63.7 mL of 0.184 M NaOH(aq) is needed to neutralize 25.0 mL of…

A: Given, 63.7 mL of 0.184 M NaOH 25.0 mL of HCl

Q: A titration of 25.00 mL sample of a hydrochloric acid solution of unknown molarity reaches the…

A: Acid reacts with base to form salt and water. This reaction is known as neutralization reaction.

Q: A chemistry student weighs out 0.166 g of ascorbic acid (H,C,H,O), a diprotic acid, into a 250. mL…

A: Ascorbic acid reacts with sodium hydroxide to form sodium ascorbate and water. The equation for the…

Q: A strong acid-strong base titration was performed as follows: 10.00 mL of 0.10M HCl were collected…

A:

Q: A 13.8 mL solution of 0.176 M phosphoric acid (ag) is to be titrated with 0.384 M sodium hydroxide…

A: The given data contains, Molarity of phosphoric acid = 0.176 M. Volume of phosphoric acid = 13.8 ml.…

Q: A strong acid-strong base titration was performed as follows: 10.00 mL of 0.10M HCl were collected…

A:

Q: By titration, it is found that 55.5 mL of 0.116 M NaOH(aq) is needed to neutralize 25.0 mL of…

A: HCl(aq)  +   NaOH (aq)  ------>   NaCl (aq)   +   H2O (l) Number of moles of HCl = Number of…

Q: By titration it is found that 35.7 mL of 0.101 M NaOH(aq) is needed to neutralize 25.0 mL of…

A: The concentration of the HCl solution after neutralisation with sodium hydroxide is determined as,

Q: By titration, it is found that 19.1 mL of 0.157 M NaOH(aq) is needed to neutralize 25.0 mL of…

A: At neutralisation point : Gram-equivalent of acid = gram equivalent of base i.e. N1×V1 = N2×V2 But,…

Q: A 1.054-g sample of KHP (potassium hydrogen phthalate, KHC3H404; molar mass = 204.22 g/mol) is…

A: Molarity of a solution is the number of moles of solute upon the volume of the solution in liters.…

Q: A strong acid-strong base titration was performed as follows: 10.00 mL of 0.10M HCl were collected…

A: Given,  Molarity of HCl = 0.10M Initial volume of HCl = 10.00 mL Volume of solution after dilution =…

Q: was performed as follows: 10.00 mL of 0.10M HCl were collected in an Erlenmeyer flask, and then…

A: D option is correct. pH = 2.15 so, nearly solution is 2.11.

Q: By titration, it is found that 39.1 mL of 0.161 M NaOH(aq) is needed to neutralize 25.0 mL of…

A: Balanced chemical equation: NaOH  +   HCl  ----->  NaCl  +  H2O Number of mmoles of NaOH = Number…

Q: A student titrated 30.mL of 0.15 M HF(aq) with 0.30 M NaOH(aq). The results are plotted on the…

A: The titration of HF with NaOH has been considered. The given questions have been solved based on the…

Q: By titration, it is found that 66.3 mL of 0.116 M NaOH(aq) is needed to neutralize 25.0 mL of…

A: Given Molarity Of NaOH = 0.116 M volume of NaOH = 66.3 ml volume of HCl = 25.0 ml

Q: By titration, it is found that 96.5 mL of 0.154 M NaOH(aq) is needed to neutralize 25.0 mL of…

A: Given information:Volume of NaOH (V1)= 96.5 mLVolume of HCl (V2)= 25.0 mLMolarity of NaOH (M1)=…

Q: By titration, it is found that 35.3 mL of 0.141 M NaOH(aq) is needed to neutralize 25.0 mL of…

A:

Q: A 19.95−mL sample of HCl of unknown concentration was transferred to a flask, a few drops of the…

A: The neutralization reaction of HCl and NaOH is given as:HCl (aq) + NaOH (aq) → NaCl (aq) + H2O…

Q: By titration, it is found that 43.1 mL of 0.180 M NaOH(aq) is needed to neutralize 25.0 mL of…

A:

Q: A chemistry student weighs out 0.106 g of ascorbic acid (H,C,H,O.), a diprotic acid, into a 250. mL…

A:

Q: By titration, it is found that 37.3 mL of 0.182 M NaOH(aq) is needed to neutralize 25.0 mL of…

A: Neutralisation Reaction : When an acid and a base reacts together to form salt and water as…

Q: Calculate the concentration of the HCl solution.

A: Macid × Vacid = Mbase × Vbase

Q: By titration, it is found that 50.1 mL of 0.192 M NaOH(aq) is needed to neutralize 25.0 mL of…

A: Given, Molarity of NaOH = 0.192 M Volume of NaOH = 50.1 ml Volume of HCl = 25.0 ml  Molarity of HCl…

Q: By titration, it is found that 62.3 mL of 0.194 M NaOH(aq) is needed to neutralize 25.0 mL of…

A: Given: The volume of NaOH= 62.3  mL Concentration of NaOH= 0.194 M Volume of HCl = 25.0 mL To…

Acid Base Titration

An acid-base titration is the method of quantitative analysis for determining the concentration of an acid and base by exactly neutralizing it with a standard solution of base or acid having known concentration.