orange is a data set about the circumference of 5 orange trees over time built in to R. use it to answer the following questions Question 3 Tree is a numeric variable True False Question 4 make a lineplot with color showing tree, and upload the imaget here Upload Choose a File Question 5

orange is a data set about the circumference of 5 orange trees over time built in to R. use it to answer the following questions Question 3 Tree is a numeric variable True False Question 4 make a lineplot with color showing tree, and upload the imaget here Upload Choose a File Question 5

Computer Networking: A Top-Down Approach (7th Edition)

7th Edition

ISBN:9780133594140

Author:James Kurose, Keith Ross

Publisher:James Kurose, Keith Ross

Chapter1: Computer Networks And The Internet

Section: Chapter Questions

Problem R1RQ: What is the difference between a host and an end system? List several different types of end...

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Here is my entire code(average is not working yet). The response I got from the professor is that I have to create a DRY solution replacing the five display_functions with a single get_array function you call five times like common_array = get_array(plant_xml, "COMMON") etc. from urllib.request import urlopenfrom xml.etree.ElementTree import parse def read_data(data_file): plant_url = urlopen(data_file) plant_xml = parse(plant_url) return plant_xml def display_common_items(plant_xml): plant_root = plant_xml.getroot() common_array = [] for item in plant_root.findall("PLANT"): common_array.append(item.find("COMMON").text) return common_array def display_botanical_items(plant_xml): plant_root = plant_xml.getroot() botanical_array = [] for item in plant_root.findall("PLANT"): botanical_array.append(item.find("BOTANICAL").text) return botanical_array def display_zone_items(plant_xml): plant_root = plant_xml.getroot() zone_array = []…
A student record system uses an ArrayList object called studrecs tomaintain a collection of student details where each student is anobject defined by the Student class. The student class has accessormethods getName() and getRegNo()Write a for-each loop that iterates through the studrecs collectionwriting out each student’s name and registration number.
use the RUST
Determine if the following statement are true or false screen shot shows the text's SortedArrayCollection and ArrayCollection When comparing two objects using the == operator, what is actually compared is the references to the objects. When comparing two objects using the equals method inherited from the Object class, what is actually compared is the references to the objects. The text's sorted array-based collection implementation stores elements in the lowest possible indices of the array. The text's array-based collection implementation stores elements in the lowest possible indices of the array.
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In python: student_dict is a dictionary with students' name and pedometer reading pairs. A new student is read from input and added into student_dict. For each student in student_dict, output the student's name, followed by "'s pedometer reading: ", and the student's pedometer reading. Then, assign average_value with the average of all the pedometer readings in student_dict..
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Python Code Create a code that can plot a distance versus time graph by importing matplotlib and appending data from a text file to a list. Follow the algorithm: Import matplotlib. Create two empty lists: Time = [ ] and Distance = [ ] Open text file named Motion.txt (content attached). Append data from Motion.txt such that the first column is placed in Time list and the second column is placed in Distance list. Plot the lists (Distance vs Time Graph). You may use this following link as a source for matplotlib functions: https://datatofish.com/line-chart-python-matplotlib/ Show Plot.
An_array and a number kFind the max elements of each of its sub-arrays of length k. Keep indexes of good candidates in deque d.The indexes in d are from the current window, they're increasing,and their corresponding nums are decreasing.Then the first deque element is the index of the largest window value. For each index i: 1. Pop (from the end) indexes of smaller elements (they'll be useless).2. Append the current index.3. Pop (from the front) the index i - k, if it's still in the deque (it falls out of the window).4. If our window has reached size k, append the current window maximum to the output..