| Boo) = (|00) + |11)) |Boi) = (l01) + |10)) |B10) = ½ ( 00) – |11)) |B1) = ½(l01) – |10)).
| Boo) = (|00) + |11)) |Boi) = (l01) + |10)) |B10) = ½ ( 00) – |11)) |B1) = ½(l01) – |10)).
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Question
Prove that the "Bell basis" in (16.23) is an orthonormal basis (Meaning, as usual, that each of these are normalized and that they are all orthogonal. You can of course assume that the starting point, (16.21), are all already normalized.)
![|00) = |0)a|0),
|01) = |0)a|1)B
|10) = |1)a|0) B
|11) = |1)a|1)B-
(16.21)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F06e9cf2e-851b-4dc5-9b25-160a0ee9894b%2F7a286de7-67cf-43f2-861d-019f5b8381bf%2Fu0bm2gj_processed.jpeg&w=3840&q=75)
Transcribed Image Text:|00) = |0)a|0),
|01) = |0)a|1)B
|10) = |1)a|0) B
|11) = |1)a|1)B-
(16.21)
![|Boo) = ½(l00) + |11)
| Bo1) = (l01) + |10))
| B10) = (100) – |11)
|B11) = (\01) – |10)).
(16.23)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F06e9cf2e-851b-4dc5-9b25-160a0ee9894b%2F7a286de7-67cf-43f2-861d-019f5b8381bf%2Fhtib3v_processed.jpeg&w=3840&q=75)
Transcribed Image Text:|Boo) = ½(l00) + |11)
| Bo1) = (l01) + |10))
| B10) = (100) – |11)
|B11) = (\01) – |10)).
(16.23)
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