Options for each:  blank 1:  A  B blank 2:   it has a better leaving group  it is a polar aprotic solvent   it has a stronger nucleophile   blank 3:  A  B blank 4:  it forms a more stable carbocation  it has a better solvent  it has a better leaving group  blank 5:  A B blank 6:  it has a better solvent  it has a better leaving group it has a stronger nucleophile

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Options for each: 

blank 1: 

  1. B

blank 2: 

  1.  it has a better leaving group 
  2. it is a polar aprotic solvent  
  3. it has a stronger nucleophile  

blank 3: 

  1. B

blank 4: 

  1. it forms a more stable carbocation 
  2. it has a better solvent 
  3. it has a better leaving group 

blank 5: 

  1. A
  2. B

blank 6: 

  1. it has a better solvent 
  2. it has a better leaving group
  3. it has a stronger nucleophile  

 

See Figure 9-7.
In 1, reaction [Select]
[Select]
In 2, reaction [Select]
[Select]
In 3, reaction [Select]
[Select]
+
is faster because
is faster because
is faster because
Transcribed Image Text:See Figure 9-7. In 1, reaction [Select] [Select] In 2, reaction [Select] [Select] In 3, reaction [Select] [Select] + is faster because is faster because is faster because
I.
Гідше 9-7
A)
B)
2. А)
B
3. А)
Br
он
DMF
Br
Br
Br
он
CH3OH
->
ензон
Д
CH3CH₂OH
Д
де сно
8) я госную
он
он
осно
OCH₂CH3
бен
Deltz
Transcribed Image Text:I. Гідше 9-7 A) B) 2. А) B 3. А) Br он DMF Br Br Br он CH3OH -> ензон Д CH3CH₂OH Д де сно 8) я госную он он осно OCH₂CH3 бен Deltz
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