Open Circuit Breaker B52. Using per unit and symmetrical component analysis, calculate the power system fault currents at Bus 2 (Line 2 out of service) for the Ø-G faults 400 MVA 15 kV B1 T1 T2 Ak 400 MVA 15/345 kV LV Δ Δ 851 0- HV Y Y 04 852 345 KV 100 mi 821 2 Line 2 Gen Xd" (per unit) X2 (per unit) 1 0.225 0.225 2 0.20 0.20 Transformer Data: Line 3 345 kV 50 mi 280 Mvar o Xpu (+/-/0) 0.06 0.05 Line 1 841 0 842 345 KV 200 mi 822 800 MW T2 800 MVA 345/15 kV XO (per unit) 0.0625 0.045 83 40 Mvar 80 MW 800 MVA 15 kV Sbase=100MVA Vbase Bus1 = 15kV Vbase Bus 3 = 15kV Vbase Lines = 345kV Neutral Reactance (pu) Xd' (per unit) Solidly grounded 0.45 0.20 0.40

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Open Circuit Breaker B52.
Using per unit and symmetrical component analysis, calculate the power system fault currents at Bus 2
(Line 2 out of service) for the Ø-G faults
400 MVA
15 kV
T1
T2
38
Ah
400 MVA
15/345 kV
LV
Δ
Δ
851
HV
Y
Y
0
Ho
B52
345 kV
100 mi
821
2-
Line 2
Gen Xd" (per unit) X2 (per unit)
1
0.225
0.225
2
0.20
0.20
Transformer Data:
Line 3
345 KV
50 mi
280 Mvard
Xpu (+/-/0)
0.06
0.05
Line 1
841
0
842
345 kV
200 mi
822
800 MW
T2
800 MVA
345/15 kV
XO (per unit)
0.0625
0.045
83
40 Mvar 80 MW
800 MVA
15 kV
Sbase = 100MVA
Vbase Bus1 = 15kV
Vbase Bus 3 = 15kV
Vbase Lines = 345kV
Neutral Reactance (pu) Xd' (per unit)
Solidly grounded
0.45
0.20
0.40
Transcribed Image Text:Open Circuit Breaker B52. Using per unit and symmetrical component analysis, calculate the power system fault currents at Bus 2 (Line 2 out of service) for the Ø-G faults 400 MVA 15 kV T1 T2 38 Ah 400 MVA 15/345 kV LV Δ Δ 851 HV Y Y 0 Ho B52 345 kV 100 mi 821 2- Line 2 Gen Xd" (per unit) X2 (per unit) 1 0.225 0.225 2 0.20 0.20 Transformer Data: Line 3 345 KV 50 mi 280 Mvard Xpu (+/-/0) 0.06 0.05 Line 1 841 0 842 345 kV 200 mi 822 800 MW T2 800 MVA 345/15 kV XO (per unit) 0.0625 0.045 83 40 Mvar 80 MW 800 MVA 15 kV Sbase = 100MVA Vbase Bus1 = 15kV Vbase Bus 3 = 15kV Vbase Lines = 345kV Neutral Reactance (pu) Xd' (per unit) Solidly grounded 0.45 0.20 0.40
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