onsider the following recursively defined sequence. t = tk-1+ 3k + 1, for each integer ka 1 to - 0 he steps below begin an iterative process to guess an explicit formula for the sequence. to- 0 - to+3. 1+1=3+ 1 t2 = t, +3. 2 +1- (3 + 1) + 3:2 +1 = 3 + 3.2+2 t3 = t, +3. 3 +1- (3 + 3. 2 + 2) + 3.3 +1 = 3+3. 2 + 3:3+ 3 ontinue the iteration process in a free response. Then guess formula for t, as a summation written in expanded form, and use Theorem 5.2.1 to write it as a single fraction whose denominator is 2. (Submit a file with a maximum size of 1 MB.) Choose File No file chosen This answer has not been graded yet

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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Consider the following recursively defined sequence.
tk = tk -1+ 3k + 1, for each integer k z 1
to = 0
The steps below begin an iterative process to guess an explicit formula for the sequence.
to = 0
t, =to + 3:1 +1=
t, = t, + 3· 2 +1 = (3 + 1) + 3. 2 + 1 = 3 + 3· 2 + 2
tz = t, + 3 ·3 +1 = (3 + 3. 2 + 2) + 3: 3 +1 = 3 + 3. 2 + 3 • 3 + 3
3 + 1
Continue the iteration process in a free response. Then guess a formula for t, as a summation written in expanded form, and use Theorem 5.2.1 to write it as a single fraction whose denominator is 2. (Submit a file with a maximum size of 1 MB.)
Choose File No file chosen
This answer has not been graded yet.
Transcribed Image Text:Consider the following recursively defined sequence. tk = tk -1+ 3k + 1, for each integer k z 1 to = 0 The steps below begin an iterative process to guess an explicit formula for the sequence. to = 0 t, =to + 3:1 +1= t, = t, + 3· 2 +1 = (3 + 1) + 3. 2 + 1 = 3 + 3· 2 + 2 tz = t, + 3 ·3 +1 = (3 + 3. 2 + 2) + 3: 3 +1 = 3 + 3. 2 + 3 • 3 + 3 3 + 1 Continue the iteration process in a free response. Then guess a formula for t, as a summation written in expanded form, and use Theorem 5.2.1 to write it as a single fraction whose denominator is 2. (Submit a file with a maximum size of 1 MB.) Choose File No file chosen This answer has not been graded yet.
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