One question with three parts

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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One question with three parts
## Concentration Table and Problem Examples

### Concentration Conversion Table

The table below provides information on the conversion of certain solutions. It lists the concentration of each solution, the given units, the desired units, and the conversion factor required.

| Concentration            | Given Units              | Desired Units         | Conversion Factor Required |
|--------------------------|--------------------------|-----------------------|----------------------------|
| 30% (m/m) NaCl solution  | grams of solution        | grams of NaCl         | Group 1                    |
| 8% (v/v) ethanol solution| milliliters of solution  | milliliters of ethanol| Group 4                    |
| 14% (v/v) fructose solution| milliliters of solution | grams of fructose     | Group 2                    |
| 5.0 M HBr solution       | moles of HBr             | liters of solution    | Group 3                    |

### Example Problems

#### Part B

A solution of rubbing alcohol is 79.2% (v/v) isopropanol in water. Calculate the milliliters of isopropanol present in a 77.7 mL sample of the rubbing alcohol solution.

- **Express your answer to three significant figures.**

> **Answer Box:** (Milliliters of isopropanol) ________________ mL

#### Part C

Determine how many liters of a 3.46 M \( \text{K}_2\text{SO}_4 \) solution are necessary to provide 86.7 g of \( \text{K}_2\text{SO}_4 \), given that the molar mass is 174.01 g/mol. Note that the symbol M represents mol/L.

- **Express your answer to three significant figures.**

> **Answer Box:** (Volume of \( \text{K}_2\text{SO}_4 \)) ________________ L

--- 

**Note:** This educational page is designed to guide students on concentration conversion and application in chemical calculations. The detailed table and examples provide a framework for solving similar problems in chemistry.
Transcribed Image Text:## Concentration Table and Problem Examples ### Concentration Conversion Table The table below provides information on the conversion of certain solutions. It lists the concentration of each solution, the given units, the desired units, and the conversion factor required. | Concentration | Given Units | Desired Units | Conversion Factor Required | |--------------------------|--------------------------|-----------------------|----------------------------| | 30% (m/m) NaCl solution | grams of solution | grams of NaCl | Group 1 | | 8% (v/v) ethanol solution| milliliters of solution | milliliters of ethanol| Group 4 | | 14% (v/v) fructose solution| milliliters of solution | grams of fructose | Group 2 | | 5.0 M HBr solution | moles of HBr | liters of solution | Group 3 | ### Example Problems #### Part B A solution of rubbing alcohol is 79.2% (v/v) isopropanol in water. Calculate the milliliters of isopropanol present in a 77.7 mL sample of the rubbing alcohol solution. - **Express your answer to three significant figures.** > **Answer Box:** (Milliliters of isopropanol) ________________ mL #### Part C Determine how many liters of a 3.46 M \( \text{K}_2\text{SO}_4 \) solution are necessary to provide 86.7 g of \( \text{K}_2\text{SO}_4 \), given that the molar mass is 174.01 g/mol. Note that the symbol M represents mol/L. - **Express your answer to three significant figures.** > **Answer Box:** (Volume of \( \text{K}_2\text{SO}_4 \)) ________________ L --- **Note:** This educational page is designed to guide students on concentration conversion and application in chemical calculations. The detailed table and examples provide a framework for solving similar problems in chemistry.
**Title: Understanding Concentration Conversions in Chemistry**

**Part A: Conversion Factor Application**

To master concentration conversions, it's crucial to appropriately apply the correct conversion factors. The exercise involves matching the concentration and unit requirements to the suitable conversion factors, ensuring accurate results when converting between units. 

**Conversion Table:**

- **Concentration:**
  - 30% (m/m) NaCl solution
  - 8% (v/v) ethanol solution
  - 14% (m/v) fructose solution
  - 5.0 M HBr solution

- **Given Units:**
  - Grams of solution
  - Milliliters of solution
  - Milliliters of HBr

- **Desired Units:**
  - Grams of NaCl
  - Milliliters of ethanol
  - Grams of fructose
  - Moles of HBr

- **Conversion Factor Required:**
  - Group 1
  - Group 4
  - Group 2
  - Group 3

Drag and drop each label into the corresponding positions to correctly assign conversion factors.

**Part B: Isopropanol Calculation**

For a solution with 79.2% (v/v) isopropanol in water, calculate the number of milliliters of isopropanol in a 77.7 mL sample. Ensure precision in your answer, expressing it to three significant figures.

Example input: [Textbox for answer entry] mL

**Learning Outcome:**

This exercise strengthens skills in identifying and applying conversion factors to solve practical chemistry problems, enhancing your understanding of solution concentrations and their real-world applications in lab settings.

**Additional Resources:**
- Pearson Education provides further guidance and tools for exploring complex chemical calculations and theory.

**Note:** This educational material is provided by Pearson Education Inc. and is subject to their Terms of Use and Privacy Policy.
Transcribed Image Text:**Title: Understanding Concentration Conversions in Chemistry** **Part A: Conversion Factor Application** To master concentration conversions, it's crucial to appropriately apply the correct conversion factors. The exercise involves matching the concentration and unit requirements to the suitable conversion factors, ensuring accurate results when converting between units. **Conversion Table:** - **Concentration:** - 30% (m/m) NaCl solution - 8% (v/v) ethanol solution - 14% (m/v) fructose solution - 5.0 M HBr solution - **Given Units:** - Grams of solution - Milliliters of solution - Milliliters of HBr - **Desired Units:** - Grams of NaCl - Milliliters of ethanol - Grams of fructose - Moles of HBr - **Conversion Factor Required:** - Group 1 - Group 4 - Group 2 - Group 3 Drag and drop each label into the corresponding positions to correctly assign conversion factors. **Part B: Isopropanol Calculation** For a solution with 79.2% (v/v) isopropanol in water, calculate the number of milliliters of isopropanol in a 77.7 mL sample. Ensure precision in your answer, expressing it to three significant figures. Example input: [Textbox for answer entry] mL **Learning Outcome:** This exercise strengthens skills in identifying and applying conversion factors to solve practical chemistry problems, enhancing your understanding of solution concentrations and their real-world applications in lab settings. **Additional Resources:** - Pearson Education provides further guidance and tools for exploring complex chemical calculations and theory. **Note:** This educational material is provided by Pearson Education Inc. and is subject to their Terms of Use and Privacy Policy.
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