One of the condition below is a condition of a linear differential equations O dependent variable and its derivatives are of degree greater than oneO term coefficients should be dependent on the unknown variableO coefficients of a term does not depend upon dependent variableO all derivative process should be in terms of the constant variable

The condition below is a condition of linear differential equation

Answered: One of the condition below is a…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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One of the strengths of numerical methods is their ability to handle complex boundary conditions. In the sketch, the boundary condition changes from specified heat flux ′′ qs (into the domain) to convection, at the location of the node (m, n). Write the steady-state, two- dimensional finite difference equation at this node.
Solve the heat equation u, = 0.2u on a digital computer using XX the Crank-Nicolson scheme. for the initial condition and boundary conditions TABLE P4.1 Case 1 2 3 4 5 Number of Grid Points 11 11 16 11 11 (x,0) = 100 sin TX L 0.25 0.50 0.50 1.00 2.00 L = 1 u(0,t) = u(L,t) = 0 Compute to t = 0.5 using the parameters in Table P4.1 (if possible) and compare graphically with the exact solution.
1 . A long cylindrical shell outer radius R₂ = 2 cm is shown in cylindrical shell is temperature Ti=10 c° and outer wall at Constant temperature T₂ = 20 C° Calculate the temperature at r= 1.5 cm (Consider conduction only) Assumptions: system is Thermal in Given: The of inner and the figure. The radial + The differential The system is: J²T dr² r maintained at steady state conductivity, K = 22.5 w/mc, system follows Fourier's law of heat Heat loss in axial direction is negligible. JT dr radius Ri=1cm Length L=lom inner Wall Constant is maintained = 0 of is Ti RI R₂ constant. conduction. equation representing Tz
please answer do not image format
2. The slab shown is embedded in insulating materials on five sides, while the front face experiences convection off its face. Heat is generated inside the material by an exothermic reaction equal to 1.0 kW/m'. The thermal conductivity of the slab is 0.2 W/mk. a. Simplify the heat conduction equation and integrate the resulting ID steady form of to find the temperature distribution of the slab, T(x). b. Present the temperature of the front and back faces of the slab. n-20- 10 cm IT- 25°C) 100 cm 100 cm

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