Bi = 1/2 PROBLEM:Solve the following 2-dimensional heat conduction problem by Gauss-Seideliteration.at center temp. node:3T2T1 + 372 + T3 + 100200AxAx4at lateral point exposed to the environment:Ду372+ 200 +2100+ 30BİT1200°FT1= 30°F2 + Bi+T3at T (at insulated surfaces):3T2100200 +AyT32400 + 3T2 + 100100°F4INSULATION

Answered: Image /qna-images/answer/060837fa-44bd-436e-b3ba-9fecc8fefdcd.jpg

PROBLEM: Solve the following 2-dimensional heat conduction problem by Gauss-Seidel iteration. 3T2 at center temp. node: T1 + 3T2 + T3 + 100 200 = Дх Ax 4 at lateral point exposed to the environment: 3T2 2 Ду + 200 + 100 + 30Bi T1 T1 = 30°F 200°F 2 + Bi T3 at T3 (at insulated surfaces): 3T2 2 100 200 + + Ду T3 400 + 3T2 + 100 100°F 4 INSULATION

PROBLEM: Solve the following 2-dimensional heat conduction problem by Gauss-Seidel iteration. 3T2 at center temp. node: T1 + 3T2 + T3 + 100 200 = Дх Ax 4 at lateral point exposed to the environment: 3T2 2 Ду + 200 + 100 + 30Bi T1 T1 = 30°F 200°F 2 + Bi T3 at T3 (at insulated surfaces): 3T2 2 100 200 + + Ду T3 400 + 3T2 + 100 100°F 4 INSULATION

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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