One cable company claims that it has excellent customer service. In fact, the company advertises that a technician will arrive within 55 minutes after a service call isplaced. One frustrated customer believes this is not accurate, daiming that it takes over 55 minutes for the cable technician to arrive. The customer asks a simple randomsample of 16 other cable customers how long it has taken for the cable technician to arrive when they have called for one the sample mean for this group is 60.1minutes with a standard deviation of 11.2 minutes. Assume that the population distribution is approximately normal. Test the customer's claim at the 0.10 level ofsignificance.Step 2 of 3: Compute the value of the test statistic. Round your answer to three decimal places

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Answered: One cable company claims that it has…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Any basketball fan knows that Shaquille O'Neal, one of the NBA's most dominant centers of the last twenty years, always had difficulty shooting free throws. Over the course of his career, his overall made free-throw percentage was 53.3%. During one off-season, Shaq had been working with an assistant coach on his free-throw technique. During the next season, a simple random sample showed that Shaq made 26 of 39 free- throw attempts. Test the claim that Shaq has significantly improved his free-throw shooting using a 0.05 significance level. Do you retain or reject the null hypothesis? Retain the null. Reject the null. Click Save and Submit to save and submit. Click Save All Answers to save all answers. Save All Answers Module 6--Assig....pdf PainNormalitylinf...pdf DIC. étv 9国回。 13 G Buscar o escribir URL
A nationwide job recruiting firm wants to compare the annual incomes for childcare workers in New York and Illinois. Due to recent trends in the childcare industry, the firm suspects that the that the mean annual income of childcare workers in the state of New York is greater than the mean annual income of childcare workers in Illinois. To see if this is true, the firm selected a random sample of 20 childcare workers from New York and an independent random sample of 20 childcare workers from Illinois and asked them to report their mean annual income. The data obtained were as follows. Annual income in dollars New York 46686 , 34979 , 47325 , 48892 , 51128 , 56792 , 47785 , 48995 , 57301 , 55176 , 48002 , 45718 , 50351 , 58527 , 47067 , 53699 , 54361 , 49727 , 36426 , 50870 Illinois 48009 , 46871 , 42774 , 49790 , 43163 , 45401 , 41068 , 50300 , 47064 , 42003 , 47775 , 41917…
A nationwide job recruiting firm wants to compare the annual incomes for childcare workers in Illinois and Massachusetts. Due to recent trends in the childcare industry, the firm suspects that the that the mean annual income of childcare workers in the state of Illinois is greater than the mean annual income of childcare workers in Massachusetts. To see if this is true, the firm selected random sample of 25 childcare workers from Illinois and an independent random sample of 25 childcare workers from Massachusetts and asked them to report their mean annual income. The data obtained were as follows. Annual income in dollars 45679, 47412, 38478, 44646, 44364, 45265, 41423, 45861, 45936, 34016, 43020, 4960o8, 43710, 45738, 41546, 38681, 34889, 39468, 45463, 53593, 40847, 38255, 45708, 57662, 54356 Illinois 41743, 36349, 44588, 40341, 32544, 38226, 46463, 42255, 38621, 32502, 37378, 40215, 41155, 38509, 47586, 46910, 56502, Massachusetts 48907, 41861, 51211, 55186, 39078, 48263, 48059,…
Two popular brands of tires for tractor-trailers are the Puma and the Eternal. Salma is a buyer for a major shipping company and wants to determine if there is any difference between the two brands of tire in the mean distance (in thousands of km) driven on them before they need to be replaced. In the company's testing lab, Salma tests a random sample of 14 Puma tires and a random sample of 15 Eternal tires. (These samples are chosen independently.) For the Puma tires, the sample mean distance (in thousands of km) until they would need to be replaced is 54.71 with a sample variance of 5.95. For the Eternal tires, the sample mean distance (in km) until they would need to be replaced is 50.21 with a sample variance of 37.75. Assume that the two populations of distances driven are approximately normally distributed. Can Salma conclude, at the 0.05 level of significance, that there is a difference between the population mean of the distances (in thousands of km) driven on Puma tires before…
An adventure company runs two obstacle courses, Fundash and Coolsprint. The designer of the courses suspects that the mean completion time of Fundash is not equal to the mean completion time of Coolsprint. To test this, she selects 205 Fundash runners and 300 Coolsprint runners. (Consider these as random samples of the Fundash and Coolspring runners.) The 205 Fundash runners complete the course with a mean time of 76.7 minutes and a standard deviation of 5.3 minutes. The 300 Coolsprint runners complete the course with a mean time of 77.5 minutes and a standard deviation of 5.1 minutes. Assume that the population standard deviations of the completion times can be estimated to be the sample standard deviations, since the samples that are used to compute them are quite large. At the 0.05 level of significance, is there enough evidence to support the claim that the mean completion time, ,, of Fundash is not equal to the mean completion time, μ₂, of Coolsprint? Perform a two-tailed test.…
An adventure company runs two obstacle courses, Fundash and Coolsprint. The designer of the courses suspects that the mean completion time of Fundash is not equal to the mean completion time of Coolsprint. To test this, she selects 250 Fundash runners and 285 Coolsprint runners. (Consider these as random samples of the Fundash and Coolspring runners.) The 250 Fundash runners complete the course with a mean time of 76.7 minutes and a standard deviation of 5.7 minutes. The 285 Coolsprint runners complete the course with a mean time of 77.5 minutes and a standard deviation of 5.6 minutes. Assume that the population standard deviations of the completion times can be estimated to be the sample standard deviations, since the samples that are used to compute them are quite large. At the 0.05 level of significance, is there enough evidence to support the claim that the mean completion time, u, of Fundash is not equal to the mean completion time, µa, of Coolsprint? Perform a two-tailed test.…
According to Forbes, the average age of millionaires in the US 10 years ago was 62 years old. Since then, the number of millionaires in the US has grown to over 17 million. One prevalent belief among economists is that the average age of millionaires today has decreased from the average age of millionaires 10 years ago. To investigate this belief, a random sample of 50 millionaires from the US was selected and their ages were recorded. Here are the summary statistics. Based on this sample, is there convincing evidence that the true mean age of millionaires in the US is less than 62 years old? Use a = 0.01. Provide statistical evidence to support your answer.
A graduate student is interested in how viewing different types of scenes affects working memory. For his study, he selects a random sample of 36 adults. The subjects complete a series of working memory tests before and after walking in an urban setting. Before the walk, the mean score on the test of working memory was 9.1. After the walk, the mean score was 1.4 higher. The graduate student has no presupposed assumptions about how viewing different types of scenes affects working memory, so he formulates the null and alternative hypotheses as: H00 : μDD = 0 H11 : μDD ≠ 0 Assume that the data satisfy all of the required assumptions for a repeated-measures t test. The graduate student calculates the following statistics for his hypothesis test: Mean difference (MDD) 1.4 Estimated population standard deviation of the differences (s) 1.6 Estimated standard error of the mean differences (sMDMD) 0.2667 Degrees of freedom (df) 35 The t statistic 5.25 The critical values of t…
A dietician read in a survey that 70.5% of adults in the U.S. do not eat breakfast at least 3 days a week. She believes that the proportion that skip breakfast 3 days a week is different than 0.705. To verify her claim, she selects a random sample of 71 adults and asks them how many days a week they skip breakfast.. 44 of them report that they skip breakfast at least 3 days a week. Test her claim at a = 0.10. The correct hypotheses would be: О Но:р 0.705 (claim) Но: р > 0.705 HA:p < 0.705 (claim) О Но: р — 0.705 HA:P + 0.705 (claim) Since the level of significance is 0.10 the critical value is 1.645 and -1.645 The test statistic is: (round to 3 places) The p-value is: (round to 3 places) The decision can be made to: O reject Ho O do not reject Ho The final conclusion is that: O There is enough evidence to reject the claim that the proportion that skip breakfast 3 days a week is different than 0.705. O There is not enough evidence to reject the claim that the proportion that skip…
It currently takes users a mean of 2626 minutes to install the most popular computer program made by RodeTech, a software design company. After changes have been made to the program, the company executives want to know if the new mean is now different from 2626 minutes so that they can change their advertising accordingly. A simple random sample of 5151 new customers are asked to time how long it takes for them to install the software. The sample mean is 24.924.9 minutes with a standard deviation of 2.72.7 minutes. Perform a hypothesis test at the 0.0250.025 level of significance to see if the mean installation time has changed. Step 1 of 3 : State the null and alternative hypotheses for the test. Fill in the blank below. H0Ha: μ=26: μ⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯26
Fran is training for her first marathon, and she wants to know if there is a significant difference between the mean number of miles run each week by group runners and individual runners who are training for marathons. She interviews 42 randomly selected people who train in groups and finds that they run a mean of 47.1 miles per week. Assume that the population standard deviation for group runners is known to be 4.4 miles per week. She also interviews a random sample of 47 people who train on their own and finds that they run a mean of 48.5 miles per week. Assume that the population standard deviation for people who run by themselves is 1.8 miles per week. Test the claim at the 0.01 level of significance. Let group runners training for marathons be Population 1 and let individual runners training for marathons be Population 2. Step 2 of 3 : Compute the value of the test statistic. Round your answer to two decimal places.
According to previous studies, the mean distance each visitor in Greenspan National Park hikes during their visit is 30 kilometers. The park recently closed its shuttle system, which used to transport hikers to many of the park's most popular hiking trails. Because of this, an administrator at the park suspects the mean distance, u, is now less than 30 kilometers. The administrator chooses a random sample of 45 visitors. The mean distance hiked for the sample is 27.2 kilometers. Assume the population standard deviation is 9.9 kilometers. Can the administrator conclude that the mean distance hiked by each visitor is now less than 30 kilometers? Perform a hypothesis test, using the 0.10 level of significance. (a) State the null hypothesis H, and the alternative hYpothesis H,. O

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