Once an individual has been infected with a certain disease, let X represent the time (days) that elapses before the individual becomes infectious. An article proposes a Weibull distribution with a = 2.6, B = 1.8, and y = 0.5. [Hint: The two-parameter Weibull distribution can be generalized by introducing a third parameter y, called a threshold or location parameter: replace x in the equation below, xa - le-(x/B)a Ba a x 20 f(x; a, B) = x < 0 by x - y and x 2 0 by x 2 y.] (a) Calculate P(1 < X < 2). (Round your answer to four decimal places.) 0.4283 (b) Calculate P(X > 1.5). (Round your answer to four decimal places.) 0.8050 (c) What is the 90th percentile of the distribution? (Round your answer to three decimal places.) 1.878 x days (d) What are the mean and standard deviation of X? (Round your answers to three decimal places.) mean days standard deviation days

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