Suppose that the probability that a patient admitted in a hospital is diagnosed with a certain type of cancer is 0.03. Suppose that on a given day 10 patients are admitted and X denotes the number of patients diagnosed with this type of cancer. The mean and the variance of Xare: None of these O E(X)=0.5 and V(X)=0.475 O E(X)=0.4 and V(X)=0.384 O E(X)=0.3 and V(X)=0.291

A First Course in Probability (10th Edition)
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Chapter1: Combinatorial Analysis
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Suppose that the probability that a patient admitted in a hospital is diagnosed with a
certain type of cancer is 0.03. Suppose that on a given day 10 patients are admitted and X
denotes the number of patients diagnosed with this type of cancer.
The mean and the variance of X are:
None of these
E(X)=0.5 and V(X)=0.475
E(X)=0.4 and V(X)=0.384
E(X)=0.3 and V(X)=0.291
Transcribed Image Text:Suppose that the probability that a patient admitted in a hospital is diagnosed with a certain type of cancer is 0.03. Suppose that on a given day 10 patients are admitted and X denotes the number of patients diagnosed with this type of cancer. The mean and the variance of X are: None of these E(X)=0.5 and V(X)=0.475 E(X)=0.4 and V(X)=0.384 E(X)=0.3 and V(X)=0.291
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