Find the exact mean value of X using the lowest common denominator and find the exact variance of X expressed using the lowest common denominator (as a fraction).

A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
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Please answer the second part of my question as given below:

Find the exact mean value of X using the lowest common denominator and find the exact variance of X expressed using the lowest common denominator (as a fraction).

I've attached the answer to the first part of the question for context. Please explain and show working. Thankyou!

1a) Derive the cumulative distribution function from the PDF
The CDF is found by integrating the PDF
PDF f(x) = 40-x
800
CDF :
0
F(x) =
40-x dx
800
40x-1/2x²
800
x
-
1
2
O
40x-1/2x²
800
0≤x≤ 40, and 0 otherwise.
40x-1/2x²
800
40x-1/2x²
800
x<0
0≤x≤ 40
x> 40
40x-1/2x²
800
x
Transcribed Image Text:1a) Derive the cumulative distribution function from the PDF The CDF is found by integrating the PDF PDF f(x) = 40-x 800 CDF : 0 F(x) = 40-x dx 800 40x-1/2x² 800 x - 1 2 O 40x-1/2x² 800 0≤x≤ 40, and 0 otherwise. 40x-1/2x² 800 40x-1/2x² 800 x<0 0≤x≤ 40 x> 40 40x-1/2x² 800 x
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