The charge stored on a capacitor's plates increases from an initial value of 40 mC to a maximum of 60 mC, and then decreases to zero, varying with time according to the graph shown here.i(t) = 50i(t) = 60q (mC)i(t) = 1010080402050symbolic formatting help1001 (ms)What is the current i(t) flowing through this capacitor as a function of time?150200XA, for 0 < t < 10 msXA, for 10 < t < 65 msXA, for 65 < t < 230 ms

Answered: The charge stored on a capacitor's…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

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The charge stored on a capacitor's plates increases from an initial value of 40 mC to a maximum of 60 mC, and then decreases to zero, varying with time according to the graph shown here.
i(t) = 50
i(t) = 60
q (mC)
i(t) = 10
100
80
40
20
50
symbolic formatting help
100
1 (ms)
What is the current i(t) flowing through this capacitor as a function of time?
150
200
XA, for 0 < t < 10 ms
XA, for 10 < t < 65 ms
XA, for 65 < t < 230 ms

Expert Solution

Step 1

Given:

Charge variation on capacitor plates with respect to time,

To find:

Current i(t) flowing through this capacitor as a function of time.

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Follow-up Question

For some reason it's saying the 0.3636 is wrong. I tried 0.364 as well thinking it may be have wanted it rounded. This is explained very well. Thank you. On the second part, you did 60-60 because the charge didn't change. Is that correct?

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