The charge stored on a capacitor's plates increases from an initial value of 40 mC to a maximum of 60 mC, and then decreases to zero, varying with time according to the graph shown here. a(MC) (t)= 50 (t) = 60 i(t) = 100 60 40 20 50 symbolic formatting help 100 150 (ms) What is the current i(t) flowing through this capacitor as a function of time? 200 XA, for 0 < t < 10 ms X A, for 10 < t < 65 ms XA, for 65 < t < 230 ms.
The charge stored on a capacitor's plates increases from an initial value of 40 mC to a maximum of 60 mC, and then decreases to zero, varying with time according to the graph shown here. a(MC) (t)= 50 (t) = 60 i(t) = 100 60 40 20 50 symbolic formatting help 100 150 (ms) What is the current i(t) flowing through this capacitor as a function of time? 200 XA, for 0 < t < 10 ms X A, for 10 < t < 65 ms XA, for 65 < t < 230 ms.
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Transcribed Image Text:The charge stored on a capacitor's plates increases from an initial value of 40 mC to a maximum of 60 mC, and then decreases to zero, varying with time according to the graph shown here.
i(t) = 50
i(t) = 60
q (mC)
i(t) = 10
100
80
40
20
50
symbolic formatting help
100
1 (ms)
What is the current i(t) flowing through this capacitor as a function of time?
150
200
XA, for 0 < t < 10 ms
XA, for 10 < t < 65 ms
XA, for 65 < t < 230 ms
Expert Solution
Step 1
Given:
Charge variation on capacitor plates with respect to time,
To find:
Current i(t) flowing through this capacitor as a function of time.
Step by step
Solved in 2 steps with 1 images
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Follow-up Question
For some reason it's saying the 0.3636 is wrong. I tried 0.364 as well thinking it may be have wanted it rounded. This is explained very well. Thank you. On the second part, you did 60-60 because the charge didn't change. Is that correct?
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