on the exam. She gives one of her two statistics clasS w day: X = 83.3, s= 4.1; n= 68 eview day: X = 80.7; s= 2.8; n= 68 cond review day was effective in in helping students prepare for the exam, the teacher would want to show that he extra review day had a statistically significant lower average than the class without. the extra review day had a statistically significant higher average than the class without. s had the same average. othesis test has been conducted by the researcher (using the 0.05 level of significance). The test statistic is t= 4.32 and the corresp Read each choice carefully. value is less than 0.05, we will reject the null hypothesis. Thus, we can say that the class with an extra review day had a significantly value is less than 0.05, we cannot reject the null hypothesis. Thus, we cannot say that the class with an extra review day had a sign value is not less than 0.05, we cannot reject the null hypothesis. Thus, we cannot say that the class with an extra review day had a O 06 we will reiect the null hypothesis. Thus, we can say that the class with an extra review day had a significa

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A teacher wants to determine if having an extra review day for a test helps students perform better on the exam. She gives one of her two statistics classes an extra review day. The mean score for each class is found and the results are given below.

Class with extra review day: \( \bar{X} = 83.3, \, s = 4.1, \, n = 68 \)  
Class without extra review day: \( \bar{X} = 80.7, \, s = 2.8, \, n = 68 \)

a. To test if the second review day was effective in helping students prepare for the exam, the teacher would want to show that
- **A.** the class with the extra review day had a statistically significant lower average than the class without
- **B.** the class with the extra review day had a statistically significant higher average than the class without
- **C.** the two classes had the same average

b. Assume that a hypothesis test has been conducted by the researcher (using the 0.05 level of significance). The test statistic is \( t = 4.32 \) and the corresponding \( p \)-value is \( 1.6429022 \, E - 4 \). What conclusion can you draw about the extra review day? Read each choice carefully.

- **A.** Since the \( p \)-value is less than 0.05, we will reject the null hypothesis. Thus, we can say that the class with an extra review day had a significantly higher average than the class without the review day.
- **B.** Since the \( p \)-value is less than 0.05, we cannot reject the null hypothesis. Thus, we cannot say that the class with an extra review day had a significantly higher average than the class without the review day.
- **C.** Since the \( p \)-value is not less than 0.05, we cannot reject the null hypothesis. Thus, we cannot say that the class with an extra review day had a significantly higher average than the class without the review day.
- **D.** Since the \( p \)-value is not less than 0.05, we will reject the null hypothesis. Thus, we can say that the class with an extra review day had a significantly higher average than the class without the review day.
Transcribed Image Text:A teacher wants to determine if having an extra review day for a test helps students perform better on the exam. She gives one of her two statistics classes an extra review day. The mean score for each class is found and the results are given below. Class with extra review day: \( \bar{X} = 83.3, \, s = 4.1, \, n = 68 \) Class without extra review day: \( \bar{X} = 80.7, \, s = 2.8, \, n = 68 \) a. To test if the second review day was effective in helping students prepare for the exam, the teacher would want to show that - **A.** the class with the extra review day had a statistically significant lower average than the class without - **B.** the class with the extra review day had a statistically significant higher average than the class without - **C.** the two classes had the same average b. Assume that a hypothesis test has been conducted by the researcher (using the 0.05 level of significance). The test statistic is \( t = 4.32 \) and the corresponding \( p \)-value is \( 1.6429022 \, E - 4 \). What conclusion can you draw about the extra review day? Read each choice carefully. - **A.** Since the \( p \)-value is less than 0.05, we will reject the null hypothesis. Thus, we can say that the class with an extra review day had a significantly higher average than the class without the review day. - **B.** Since the \( p \)-value is less than 0.05, we cannot reject the null hypothesis. Thus, we cannot say that the class with an extra review day had a significantly higher average than the class without the review day. - **C.** Since the \( p \)-value is not less than 0.05, we cannot reject the null hypothesis. Thus, we cannot say that the class with an extra review day had a significantly higher average than the class without the review day. - **D.** Since the \( p \)-value is not less than 0.05, we will reject the null hypothesis. Thus, we can say that the class with an extra review day had a significantly higher average than the class without the review day.
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