On the basis of extensive tests, the yield point of a particular type of mild steel-reinforcing bar is known to be normally distributed witho 100. The composition of the bar has been slightly modified, but the modification is not believed to have affected either the normality orthe value of a.(a) Assuming this to be the case, if a sample of 25 modified bars resulted in a sample average yield point of $407 To, compute a90% CI for the true average yield point of the modified bar. (Round your answers to one decimal place.)lb(b) How would you modify the interval in part (a) to obtain a confidence level of 96%2 (Round your answer to two decimal places)-Select-should be changed toYou may need to use the appropriate table in the Appendix of Tables to answer this question.Need Help? Read II

Given x-bar=8407 Standard deviations=100 n=25

Answered: On the basis of extensive tests, the…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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For the coefficient of an independent variable to be statistically significant and accepted as a valid estimate of the population coeficient, the prob. (or p-value) associated with the coefficient must be: O less than 0.01 O larger than 0.10 equal to or less than 0.05 O less than 1.00.
1.3.2 Consider the output given below that was obtained using the One Proportion applet. Use information from the output to find the standardized statistic for a sample propor- tion value of 0.45. Probability of success (n): 0.30 Sample size (n): 25 Number of samples: 1000 O Animate Draw Samples Total = 1000 180 Mean = 0.301 SD = 0.091 120 60 0.08 0.16 0.24 0.32 0.40 0.48 0.56 0.64 Proportion of success
Consider a sample of n = 114 women drawn randomly from the membership list of the National Organization for Women (N.O.W.), x = 24 of whom were found to smoke. Use the result of this sample to test whether the rate found is significantly different from the United States proportion of 0.31 for women and provide the z-statistic value below.
You obtain a t comp of .975 in a two sample independent t test with alpha at .05. Is it significant?
Q.8.3 A shop owner claims that on average, his shop has a daily turnover of R75 000. Test this claim at the 5% significance level, if the average daily turnover for a sample of 88 days was R71 500. Assume a population standard deviation of R4 450.
According to the Official Stage Magician Handbook, magic rabbit weight (Ibs.) is normally distributed with u = 6.2 and o = 1.5. %3D Consider obtaining a random sample of 3 magic rabbits. Would it be unusual for the sample mean to be at least 6.5? Why or why not? Yes because the z-score corresponding to a sample mean of 6.5 would be z = 0.34. No because the z-score corresponding to a sample mean of 6.5 would be z = 0.34. O Yes because the z-score corresponding to a sample mean of 6.5 would be z = 0.20. O No because the z-score corresponding to a sample mean of 6.5 would be z = 0.20.
A researcher conducted a repeated measures study comparing three treatment conditions. Refer to attached images and tale to answer a to d. Mean Std. Deviation N Treatment I 1.00 1.414 5 Treatment II 5.00 2.345 5 Treatment III 6.00 1.581 5 In APA format, report the F-ratio related to the treatment effect: Is this treatment effect significant? What is the partial η2 value for the treatment effect? Is this a weak, moderate, or strong effect?
A manufacturer of children's vitamins claims that its vitamins are mixed so that each batch has exactly the following percentages of each color: 20 % green, 30 % yellow, 30% red, and 20% orange. To test the claim that these percentages are incorrect, 100 bottles of vitamins were sampled and the colors of the vitamins were tallied. The results are listed in the following table. At a = 0.025, determine whether there is sufficient evidence to conclude that the percentages stated by the vitamin manufacturer are incorrect. Number Children's Vitamins Green 906 I Yellow 1321 Porange Red 1306 Copy Data Step 1 of 4: State the null and alternative hypotheses in terms of the expected proportion for each color of vitamin. Ho:P green = - Pyellow = _Pred = Ha: There is a difference from the stated proportions. Orange 778
1.

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