You obtain a t comp of .975 in a two sample independent t test with alpha at .05. Is it significant?
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You obtain a t comp of .975 in a two sample independent t test with alpha at .05. Is it significant?
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- Sal knows that parties of people on average spend 75 minutes at their restaurant. They wonder if this average is significantly different on the weekends. They found the average time spent by the 30 parties which dined there this weekend was 82 minutes with a SD of 17 minutes. Assume an alpha of .05. What is the test statistic?Is it more conservative to use an alpha level of .01 or an alpha level of .05? Would beta be higher for an alpha of .05 or for an alpha of .01?. Differences of electric potential occur naturally from point to point on a body’s skin. Researchers used newts to determine if changing the electric field reduces the mean healing rate for all newts. The researchers found in a sample of 14 newts the following data results: ?̅= −5.714 with sd = 10.564. Conduct a paired t-test at α = .01 to determine if there is sufficient evidence to conclude that changing the electric field reduces the mean healing rate for all newts.
- Andre recenty found a die (the traditional, six-sided variety) at the park. He took it home and rolled it 100 times and recorded the results (found in the table below). Is this a 'fair die' or has it been tampered with? Test at the alpha = 0.01 level of significance. Roll count: Rolled: Count: 1 1 2 8 3 9 4 6 5 4 6 72 What is the test statistic (2 dec. Places)Use the table of critical values of the Pearson correlation coefficient to determine whether the correlation coefficient is statistically significant at the specified level of significance for the given sample size. Write the critical value to the nearest thousandth. r=0.998r=0.998, α=0.01α=0.01, n=4 Is the correlation coefficient statistically significant?Determine whether the given correlation coefficient is statistically significant at the specified level of significance and sample size. r=−0.599 α=0.01, n=11 Yes or No?
- You obtain a sample chi-square value of x2= -5.49. On the basis of this value, you know that a. there is a negative association between your two variables. b. the observed frequencies are higher than the expected frequencies across at least half of your cells. c. you have made a calculation error; chi-square values cannot be negative. d. the observed frequencies are lower than the expected frequencies across all cells.The Road Department is trying to see whether they should buy road treatments ( in tons) for storms based on the number of inches of snow for each recorded. Use Pearson r at alpha- 0.05 to test the hypothesis. ILLUSTRATE THE NORMAL CURVE inches in snow 1.5 1.7 3.7 2.8 4.6 2.4 3.1 2.9 3.6 4.2 3.1 number of tons 805 905 1235 1000 1302 998 1102 1305 1456 1600 1005andres asked if there is a relationship between the quality of sneakers worn by a sample of 20 volleyball players and their average number of point scored per game. he computed r= +.21 and immediately claimed he had evidence that better-quality sneakers are related to better performance (a) is his claim correct? why? (b) what are Ho and Ha? (c) with alpha=.05, what is rcrit ?
- In reporting the results of a statistical analysis, a researcher reports that "p = .33". This implies that ________. a. the alternative hypothesis was accepted with an alpha level of .05 b. the alternative hypothesis was not accepted with an alpha level of .05 c. the null hypothesis was not rejected with an alpha level of .05 d. the null hypothesis was rejected with an alpha level of .05A random sample of n = 25 individuals is selected from a population with u = 20, and a treatment is administered to each individual in the sample. After treatment, the sample mean is found to be M = 22.2 with SS = 384. PLEASE SHOW HOW YOU GOT YOUR Answer. a. How much difference is there between the mean for the original population? (Note; In a hypothesis test, this value forms the numerator of the t statistic.) b. If there is no treatment effect, how much difference is expected between the sample mean and its population mean? That is, find the standard error for M. (Note: In a hypothesis test, this value is denominator of the t statistic.) c. Based on the sample data, does the treatment have a significant effect? Use a two-tailed test with a = .05.Harvard University claims 64% of its Harvard Business School students earn internships on wall street. Fred disagrees, claiming it should be higher. He samples a population of 6745 Harvard Business School Students and finds that 4435 have jobs lined up on Wall Street. If alpha=.05, is Fred's assertion correct? What is the p-value of Fred's test? Round to the nearest 6 decimals