On Raymond Island, "knights" always tell the truth, "knaves" always lie, and "normals" sometimes tell the truth and sometimes lie. You meet 4 islanders, denoted A, B, C, D. At least one is a knight, and at least one is a knave. They state: A: B is a knight or C is a knight. B: If D is a knave, then A is a knight. C: If A is a knight, then B is a knight. D: If C is a knave, then A is a knight. 1. Briefly restate the question. 2. Define and translate the problem into notation. (Often best mixed with 1. Latex is good, or here are symbols you can copy: ¬AV →→ Ⓡ) 3. Give your final conclusion: who are the knights and who are the knaves and who are the normals. 4. Present the evidence, reasoning, and/or method that produced that conclusion. On Raymond Island it will be especially important to restate and define notation, since, e.g., an islander that is not a knight is not necessarily a knave and doesn't necessarily tell lies. A: B is a knight or C is a knight.: A+(BvC) B: If D is a knave, then A is a knight.: B+(-D-A) C: If A is a knight, then B is a knight. : C+(A→B) D: If C is a knave, then A is a knight. : D+(-C-A)

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Who is a knight and who is a knave?

This is a discrete structures problem. What I have written in the box is my answer so far the only problem is is that according to a truth table I made they are all knights which is not possible.

On Raymond Island, "knights" always tell the truth, "knaves" always lie, and
"normals" sometimes tell the truth and sometimes lie. You meet 4 islanders,
denoted A, B, C, D. At least one is a knight, and at least one is a knave. They
state:
A: B is a knight or C is a knight.
B: If D is a knave, then A is a knight.
C: If A is a knight, then B is a knight.
D: If C is a knave, then A is a knight.
1. Briefly restate the question.
2. Define and translate the problem into notation. (Often best mixed with 1. Latex is
good, or here are symbols you can copy: AV →→ Ⓡ)
3. Give your final conclusion: who are the knights and who are the knaves and who are
the normals.
4. Present the evidence, reasoning, and/or method that produced that conclusion.
On Raymond Island it will be especially important to restate and define
notation, since, e.g., an islander that is not a knight is not necessarily a knave
and doesn't necessarily tell lies.
A: B is a knight or C is a knight. : A+(BvC)
B: If D is a knave, then A is a knight.: B+(-D-A)
C: If A is a knight, then B is a knight.: C+(A→B)
D: If C is a knave, then A is a knight.: D+(-C-A)
All the
Transcribed Image Text:On Raymond Island, "knights" always tell the truth, "knaves" always lie, and "normals" sometimes tell the truth and sometimes lie. You meet 4 islanders, denoted A, B, C, D. At least one is a knight, and at least one is a knave. They state: A: B is a knight or C is a knight. B: If D is a knave, then A is a knight. C: If A is a knight, then B is a knight. D: If C is a knave, then A is a knight. 1. Briefly restate the question. 2. Define and translate the problem into notation. (Often best mixed with 1. Latex is good, or here are symbols you can copy: AV →→ Ⓡ) 3. Give your final conclusion: who are the knights and who are the knaves and who are the normals. 4. Present the evidence, reasoning, and/or method that produced that conclusion. On Raymond Island it will be especially important to restate and define notation, since, e.g., an islander that is not a knight is not necessarily a knave and doesn't necessarily tell lies. A: B is a knight or C is a knight. : A+(BvC) B: If D is a knave, then A is a knight.: B+(-D-A) C: If A is a knight, then B is a knight.: C+(A→B) D: If C is a knave, then A is a knight.: D+(-C-A) All the
Expert Solution
Step 1

To solve this problem, we need to determine who the knights and villains are on Raymond Island. We can use propositional logic and truth tables to analyze the statements of the four islanders, A, B, C, and D.

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