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Define the rule echoN(LST0, LST1, CNT). This rule determines when LST1 consists of only CNT repetitions of the elements in list LSTO. *don't worry if it infinitely loops on determining the source list (i.e. echoN(A. [a,a,b,b],1).) e.g.: |?- echoN([a,b], [a,a,b,b], A). A = 1? yes |?- echoN([a,b], A, 1). A = [a,a,b,b] ? yes | 2- echoN([a.[b.c],d], A. 2). A = [a,a,a, [b.c],[b.c],[b.c],d.d.d] ? yes

Define the rule echoN(LST0, LST1, CNT). This rule determines when LST1 consists of only CNT repetitions of the elements in list LSTO. *don't worry if it infinitely loops on determining the source list (i.e. echoN(A. [a,a,b,b],1).) e.g.: |?- echoN([a,b], [a,a,b,b], A). A = 1? yes |?- echoN([a,b], A, 1). A = [a,a,b,b] ? yes | 2- echoN([a.[b.c],d], A. 2). A = [a,a,a, [b.c],[b.c],[b.c],d.d.d] ? yes

Database System Concepts
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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pls anwser in prolog language, thank you.

Define the rule echoN(LST0, LST1, CNT). This rule determines when LST1 consists of only CNT repetitions of the elements in list LSTO. *don't worry if it infinitely loops on determining the source list (i.e. echoN(A,[a,a,b,b],1).) e.g.: | ?- echoN([a,b], [a,a,b,b], A). A = 1? yes | 2- echoN([a,b], A, 1). A = [a,a,b,b] ? yes |?- echoN([a,[b.c],d], A, 2). A = [a,a,a,[b,c],[b,c],[b,c],d,d,d] ? yes
Transcribed Image Text:Define the rule echoN(LST0, LST1, CNT). This rule determines when LST1 consists of only CNT repetitions of the elements in list LSTO. *don't worry if it infinitely loops on determining the source list (i.e. echoN(A,[a,a,b,b],1).) e.g.: | ?- echoN([a,b], [a,a,b,b], A). A = 1? yes | 2- echoN([a,b], A, 1). A = [a,a,b,b] ? yes |?- echoN([a,[b.c],d], A, 2). A = [a,a,a,[b,c],[b,c],[b,c],d,d,d] ? yes
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