Solve the problem.Suppose that n trials of a binomial experiment result in no successes. According to the "Rule of Three", wehave 95% confidence that the true population proportion has an upper bound of 3/n. If a manufacturerrandomly selects 25 computers for quality control and finds no defective computers, what statement can youmake by using the rule of three, about the proportion p, of all its computers which are defective?We are 95% confident that p does not exceed-3OWe are 95% confident that p is greater than 25O We are 95% confident that p lies betweenThe value of p cannot be greater than33and625

According to the Rule of Three we have 95% confidence that the true population proportion has an…

Answered: -olve the problem. Suppose that n…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Three students, Linda, Tuan, and Javier, are given five laboratory rats each for a nutritional experiment. Each rat's weight is recorded in grams. Linda feeds her rats Formula A, Tuan feeds his rats Formula B, and Javier feeds his rats Formula C. At the end of a specified time period, each rat is weighed again, and the net gain in grams is recorded. Using a significance level of 10%, test the hypothesis that the three formulas produce the same mean weight gain. (Let 1 = Linda's rats, 2 = Tuan's rats and 3 = Javier's rats.) Weights of Student Lab Rats Linda's rats Tuan's rats Javier's rats 43.0 46.9 51.1 38.5 40.1 40.4 40.7 38.4 37.1 45.8 45.7 44.8 37.8 43.6 47.7 Part (a) State the null hypothesis. H0: ?1 = ?2 = ?3 H0: At least two of the group means ?1, ?2, ?3 are not equal. Part (b) State the alternative hypothesis. Ha: ?1 = ?2 = ?3 Ha: At least two of the group means ?1, ?2, ?3 are not equal. Part (c) Enter an exact number as an…
2
What would be the percentage of this question?
Suppose we have the results of a Gallup survey (simple random sampling) which asks participants for their opinions regarding their attitudes toward technology. Based on 1500 interviews, the Gallup report makes confidence statements about its conclusions. If 64% of those interviewed favored modern technology, we can be 95% confident that the percent of those who favored modern technology is a 95% of 64%, or 60.8% b 95% 3% c 64% d 64% 3%
When solving a problem related to one sample and the confidence interval of variance. Suppose the sample size is n. What is the degree of freedom we will use?
A researcher claims that exactly 40% of all adults in the U.S. use their cell phone for most of their online browsing. You believe that the true proportion is different. To test this, you take a simple random sample of 200 adults in the U.S and find that 39% of them use their phone for most of their online browsing. Test at 5% significance. Round to the fourth as needed How many successes were there? Ho: Select an answer HA: Select an answer Test Statistic: Select an answer Select an answer ✓ P-value: Did something significant happen? [Select an answer Select the Decision Rule: Select an answer There [Select an answer enough evidence to conclude Select an answer Build a 95% confidence interval and decide if you can conclude the same. Use your calculator to do this and round to the fourth decimal place. Can we conclude the same as our Hypothesis Test? ? ✓ because the true proportion of U.S. adults that use their cell phones for most of their online browsing Select an answer
8 A New York Times article reported that a survey conducted in 2014 included 36,000 adults, with 1,500 of them being regular users of e-cigarettes. Because e-cigarette use is relatively new, there is a need to obtain today's usage rate. How many adults must be surveyed now if we want a confidence level of 90% and a margin of error of 1.5 percentage points?
According to a recent study in New York, 15% of shoppers are unfairly being charged sales tax in non-taxable items. Mr. Hypothesis feels this proportion is too low. He tests his belief by conducting a survey of 200 random shoppers. Which of the following would be the alternate hypothesis? a. The percent of shoppers unfairly being charged sales tax on non-taxable items < .15 b. The percent of shoppers unfairly being charged sales tax on non-taxable items > .15 c. The percent of shoppers unfairly being charged sales tax on non-taxable items = .15
Suppose a 95% confidence interval for the difference in test scores between Class 1 and Class 2 (in that order) is the following: 9 +/− 2. These results were based on independent samples of size 100 from each class. Now suppose you switch the order of Class 1 and Class 2 in your analysis but keep the data labeled correctly in terms of which class they came from. Which of the following statements is false? A) You can't do it this way. You'll get negative numbers for the difference in the means and/or negative numbers for the standard error. B) You are confident that the average for Class 2 is 7 to 11 points lower than for Class 1. C) You are still confident that the classes have significantly different mean scores. D) Your 95% confidence interval will now be entirely negative: from −7 to −11.
For a sample with a mean of 10, a std of 5 and an n of 30, what is the lower bound of the 95% confidence interval?
A researcher claims that exactly 40% of all adults in the U.S. use their cell phone for most of their online browsing. You believe that the true proportion is different. To test this, you take a simple random sample of 200 adults in the U.S and find that 40% of them use their phone for most of their online browsing. Test at 5% significance. Round to the fourth as needed What's the minimum population size required? 200 How many successes were there? 80 Ho:P o 0.40 HAP o 0.40 Test Statistic: 0.00 P-value: 1.0000 Did something significant happen? Nothing Significant Happened Select the Decision Rule: Fail to Reject the Null v There is not that the proportion of all adults in the U.S. who use their cell phone for most of their online browsing is different than 0.4 v o enough evidence to conclude Build a 95% confidence interval and decide if you can conclude the same. Use your calculator to do this and round to the fourth decimal place. Can we conclude the same as our Hypothesis Test? yes o…
2. Some scientists believe that the presence of antibody to milk protein lowers the chance of survival after a heart attack. To explore this belief, a medical team took blood specimens from 335 male heart-attack patients and tested them for the presence of the antibody. The patients were then followed to determine whether they lived for 6 months following their heart attack. The results are presented in Table 2. Suppose we want to answer the following question: "Test, at the 5% level of significance, whether there is an association between the presence of antibody to milk protein and survival after a heart attack." Table 2: Survival vs Antibody to Milk Protein contingency table Survival Antibody to Milk Protein Alive Died Total Present 24 52 76 Absent 126 133 259 Total 150 185 335 SPSS produced the information needed to perform the hypothesis test in Table 3. Table 3: Chi-Square Tests Results Chi-Square Tests Asymptotic Significance (2-sided) Exact Sig. (2- sided) Exact Sig. (1- sided)…

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