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Oil at 500K is to be cooled at 5000K in a counter current exchanger using cold water available at 295K. A temperature approach of 10K is to be maintained at both ends of the exchanger. The specific heats of oil and water are 3.2 and 4.2kJ/kg.K respectively. Determine the total entropy change in the process. 350 kJ K O 600 kJ K 100 kJ K 210.1kJ K 418 kJ K

Oil at 500K is to be cooled at 5000K in a counter current exchanger using cold water available at 295K. A temperature approach of 10K is to be maintained at both ends of the exchanger. The specific heats of oil and water are 3.2 and 4.2kJ/kg.K respectively. Determine the total entropy change in the process. 350 kJ K O 600 kJ K 100 kJ K 210.1kJ K 418 kJ K

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Oil at 500K is to be cooled at 5000K in a counter current exchanger using cold water available at 295K. A temperature approach of 10K is to be maintained at both ends of the exchanger. The specific heats of oil and water are 3.2 and 4.2kJ/kg.K respectively. Determine the total entropy change in the process. O 350 kJ K O 600 kJ K 100 kJ K O210.1kJ K O 418 kJ K O
Transcribed Image Text:Oil at 500K is to be cooled at 5000K in a counter current exchanger using cold water available at 295K. A temperature approach of 10K is to be maintained at both ends of the exchanger. The specific heats of oil and water are 3.2 and 4.2kJ/kg.K respectively. Determine the total entropy change in the process. O 350 kJ K O 600 kJ K 100 kJ K O210.1kJ K O 418 kJ K O
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