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There is a 4" O.D. vertical pipe made of 316 stainless steel. Calculate the heat flux (q/A) per unit length for both free convection (h) and radiation (assume & = .25) heat transfer for the following two surface temperatures. a) T (surface) = 100 C h = 5 W/m2-k b) T (surface) = 500 C h=50 W/m2-K q/A (radiation) = σε (Ts^4 -Ta^4) o= 5.676 E-08 W/m^2 K^4 Ts surface temp Ta = air temp. =

There is a 4" O.D. vertical pipe made of 316 stainless steel. Calculate the heat flux (q/A) per unit length for both free convection (h) and radiation (assume & = .25) heat transfer for the following two surface temperatures. a) T (surface) = 100 C h = 5 W/m2-k b) T (surface) = 500 C h=50 W/m2-K q/A (radiation) = σε (Ts^4 -Ta^4) o= 5.676 E-08 W/m^2 K^4 Ts surface temp Ta = air temp. =

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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There is a 4" O.D. vertical pipe made of 316 stainless steel. Calculate the heat flux (q/A) per unit length for both free convection (h) and radiation (assume & = .25) heat transfer for the following two surface temperatures. a) T (surface) = 100 C h = 5 W/m2-k b) T (surface) = 500 C h=50 W/m2-K q/A (radiation) = 0 (Ts^4 -Ta^4) 0= = 5.676 E-08 W/m^2 K^4 Ts surface temp Ta = air temp.
Transcribed Image Text:There is a 4" O.D. vertical pipe made of 316 stainless steel. Calculate the heat flux (q/A) per unit length for both free convection (h) and radiation (assume & = .25) heat transfer for the following two surface temperatures. a) T (surface) = 100 C h = 5 W/m2-k b) T (surface) = 500 C h=50 W/m2-K q/A (radiation) = 0 (Ts^4 -Ta^4) 0= = 5.676 E-08 W/m^2 K^4 Ts surface temp Ta = air temp.
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