of 32.1 kW32.1 kW occurs during the process. You may assume that changes in kinetic and potential energy are negligible, the temperature of the surroundings is 25 ∘C,25 ∘C, and that the ?PCP of air is 3.5 R. Given the compressor operates with a second law (reversible) efficiency of 0.52,0.52, calculate the following. What is the actual work interaction term? What is the actual exit temperature of the air?

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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Air (??=29 kg/kmol)(MW=29 kg/kmol) at 112.00 kPa112.00 kPa and 295.00 K295.00 K is compressed steadily to 600.0 kPa.600.0 kPa. The mass flow rate of the air is 2.00 kg/s2.00 kg/s and a heat loss of 32.1 kW32.1 kW occurs during the process. You may assume that changes in kinetic and potential energy are negligible, the temperature of the surroundings is 25 ∘C,25 ∘C, and that the ?PCP of air is 3.5 R. Given the compressor operates with a second law (reversible) efficiency of 0.52,0.52, calculate the following.

What is the actual work interaction term?

What is the actual exit temperature of the air?

© Macmillan Learning
Air (MW = 29 kg/kmol) at 112.00 kPa and 295.00 K is compressed steadily to 600.0 kPa. The mass flow rate of the air is
2.00 kg/s and a heat loss of 32.1 kW occurs during the process. You may assume that changes in kinetic and potential energy are
negligible, the temperature of the surroundings is 25 °C, and that the Cp of air is 3.5 R. Given the compressor operates with a
second law (reversible) efficiency of 0.52, calculate the following.
What is the actual work interaction term?
actual work:
234.45
Incorrect
What is the actual exit temperature of the air?
actual exit temperature:
430.85
Incorrect
kW
C
Transcribed Image Text:© Macmillan Learning Air (MW = 29 kg/kmol) at 112.00 kPa and 295.00 K is compressed steadily to 600.0 kPa. The mass flow rate of the air is 2.00 kg/s and a heat loss of 32.1 kW occurs during the process. You may assume that changes in kinetic and potential energy are negligible, the temperature of the surroundings is 25 °C, and that the Cp of air is 3.5 R. Given the compressor operates with a second law (reversible) efficiency of 0.52, calculate the following. What is the actual work interaction term? actual work: 234.45 Incorrect What is the actual exit temperature of the air? actual exit temperature: 430.85 Incorrect kW C
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