of water at room temperature. A solution is prepared by dissolving 42 g in 100 mL of water at 80 ∘∘C. The solution is then cooled slowly to room temperature without any solid precipitating. The solution is Group of answer choices unsaturated at room temp. supersaturated at room temp. supersaturated at 80 ∘∘C
of water at room temperature. A solution is prepared by dissolving 42 g in 100 mL of water at 80 ∘∘C. The solution is then cooled slowly to room temperature without any solid precipitating. The solution is Group of answer choices unsaturated at room temp. supersaturated at room temp. supersaturated at 80 ∘∘C
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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The solubility of a substance is 36 g per 100 mL of water at room temperature. A solution is prepared by dissolving 42 g in 100 mL of water at 80 ∘∘C. The solution is then cooled slowly to room temperature without any solid precipitating. The solution is
Group of answer choices
unsaturated at room temp.
supersaturated at room temp.
supersaturated at 80 ∘∘C
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