Of 500 randomly selected college students, 200 use a particular brand of mobile phone. Assuming that every college student is a mobile phone user, for this sample, which one represents the 95% confidence interval for the proportion of the students who use this particular brand?   A ) (0.374, 0.446) B ) (0.344, 456) C ) (0.334, 0.466) D ) (0.364, 0.436) E ) (0.357, 0.443)

Q: Given that 200 items of 800 are defective, construct the following confidence intervals for the…

A:

Q: A poll of 827 students at Alpha State College found that 61% of those polled preferred a quarter…

A: Given that Sample size n = 827 Sample proportion of students who prefer a quarter system = 0.61 The…

Q: In a survey of 3005 adults aged 57 through 85 years, it was found that 81.7% of them used at least…

A: Given :  n = 3005 p̂=0.817

Q: 25.1, 22.3, 21.8, 17.1, 19.4, 29.2, 21.4, 26.5, 16.7, 19.4, 20.5 Construct a 90% confidence interval…

A: From the provided information, Sample size (n) = 11 Confidence level = 90%

Q: Compute a 95% confidence interval for the population mean μ for the average amount a shopper spends…

A: Given data is158,126,121,164,171,141,112sample size(n)=7

Q: ou are interested in constructing a 90% confidence interval for the proportion of all caterpillars…

A: Given : n = 352 x = 55 Confidence level = 90%

Q: Select all of the following choices that are possible confidence intervals on the population value…

A: The notation r represents the statistic, which is the value of the linear correlation coefficient…

Q: A newsgroup is interested in constructing a 99% confidence interval for the proportion of all…

A: The formula for the confidence interval for the proportion is,

Q: In a survey of 3015 adults aged 57 through 85 years, it was found that 85.6% of them used at least…

A:

Q: A 95% confidence intervel for the proportion of U.S. adults enjoying work from home is…

A:

Q: A newsgroup is interested in constructing a 95% confidence interval for the proportion of all…

A:

Q: A sample of 200 customers showed that 175 of them made an online purchase last year. Construct the…

A:

Q: A random sample of 500 items reveals that 325 of the items have the attribute of interest. a. What…

A: Solution: a. Let X be the number of items have the attribute of interest and n be the sample number…

Q: a reasearcher is wishing to estimate the proportion of x-ray machines that malfunction and produce…

A: It is given that sample size (n) is 40 and x is 12.

Q: A research center survey of 2,388 adults found that 1,904 had bought something online. Of these…

A: Given: n=2,388α=0.05

Q: Let p₁ be the proportion of students in English class who receive grade A, and p2 be the proportion…

A: Given,the sample proportions of Grade A in English class and Maths class.To choose the correct…

Q: Give the critical value, za/2 , for the 98% confidence level. A.) 2.33 B.) 1.645 C.) 2.575 D.) 1.96

A: For 98% CI

Q: A random sample of high school students is used to estimate the mean time all high school students…

A: Solution: From the given information, a 99% confidence interval is 1.7 hours to 3.1 hours.

Q: Step 1 of 4:   Find the mean of the paired differences, d‾. Round your answer to one decimal place.…

A: Step 1 of 4: The difference is, Husband Wife Difference (d) 51 60 -9 28 26 2 39 36 3 25…

Q: Find a 90% confidence interval for the population mean for the data set (120, 80, 83, 115, 95, 90,…

A: From the provided information, Sample size (n) = 20

Q: Five fourth-grade children were selected at random from the entire class and timed in a short race.…

A: Given data : The times in seconds were 6.3, 4.2, 4.7, 6.0, and 5.7

Q: The following data represent the smoking status by level of education for residents 18 years old or…

A: The data for the smoking status by the level of education is given.

Q: 2. In a random sample of 150 drivers arrested for DUI (drunk driving), 90% were males. The 99%…

A: According to the given information, we have Total number of drivers arrested for DUI = 150 90% were…

Q: A newsgroup is interested in constructing a 99% confidence interval for the proportion of all…

A: For 95% confidence interval for population proportion, if 95% confidence intervals are calculated…

Q: 24. Construct a 98% confidence interval for p1 – Pfrom the following data 300 pi = 0.53 - 200 î2 n2…

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Q: In a survey of 1002 people, 70% said that they voted in a recent presidential election. In…

A: n=1002

Q: a.) The individual object in the study was a randomly selected This is computer-graded so use exact…

A: Given,the 95% confidence interval for the average mean score in the final exam for each of the…

Q: A newsgroup is interested in constructing a 99% confidence interval for the proportion of all…

A:

Q: Given a 95% confidence interval for p1-p2 as (-0.98, -0.78). What can be concluded?

A: The 95% confidence interval for p1–p2 is (–0.98, –0.78).

Q: In a survey of 3293 adults aged 57 through 85​ years, it was found that 80.8​% of them used at least…

A: Given Information Total adults(n) = 3293

Q: A random sample of 500 patients with diabetes were weighed before and after switching to a new drug…

A: The objective of the question is to determine the 95% confidence interval for the average change in…

Q: Consider the following sample information randomly selected from two populations. Sample 1: n1 =250,…

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Q: You are trying to estimate the percent of people in California who have a college degree. You…

A: Given that  Sample size n =60 Favorable cases x =18 Sample proportion p^=x/n  =18/60 =0.3

Q: 1. Out of a sample of 150 people who walked into a fast-food restaurant, 135 said they prefer…

A: As per our guidelines we are suppose to answer only one…

Q: 4. From an SRS of 600 U.S. adults, 116 live in a multigenerational household (multiple generation…

A: We have given that,  Favorable cases (X) = 116 and sample size (n)=600  Then,  We will find the 95…

Q: 1- A researcher wants to learn the ratio of smoking habit among the university students. Out of 1000…

A: For male students, sample size is n = 1000 And number of students who said " yes I am smoking", X =…

Q: A simple random sample of 1000 people age 18 or over is taken in a large town. It turns out that 223…

A: From the provided information, Sample size (n) = 1000 223 people in the sample are newspaper…

Q: In a survey of 3492 adults aged 57 through 85 years, it was found that 84.6% of them used at least…

A: We have to find given confidence interval..

Q: A simple random sample of 5 observations from a normal distribution was taken, and the following…

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Q: In a survey of 3092 adults aged 57 through 85 years, it was found that 88.5% of them used at least…

A: n = 3092 Sample proportion (p̂) = 88.5% = 0.885

Q: From a random sample of 100 women, 15 have dangerous reading blood sugar levels higher than 300…

A:

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.