A research center survey of 2,490 adults found that 1,902 had bought something online. Of these online​ shoppers, 1,237 are weekly online shoppers. a.) Construct a​ 95% confidence interval estimate of the population proportion of adults who had bought something online. b.) Construct a​ 95% confidence interval estimate of the population proportion of online shoppers who are weekly online shoppers.

Q: In a survey of 3239 adults aged 57 through 85 years, it was found that 85.8% of them used at least…

A: Given : n=3239 p^=85.8%=0.858The formula for confidence interval for population proportion is…

Q: In your work for a real estate company, you find that in a sample of 1762 home buyers, 722 found…

A: Given Data: x=722 n=1762   p^=7221762=0.4098

Q: It is important for airlines to follow the published scheduled departure times of flights. Suppose…

A: a) It is given that sample size (n) is 246 and the number of flights were on-time departures (x) is…

Q: In a survey of 3005 adults aged 57 through 85 years, it was found that 81.7% of them used at least…

A: Given :  n = 3005 p̂=0.817

Q: According to a Harris Interactive survey of 2401 adults conducted in April 2009, 25% of adults do…

A:

Q: Sixty-five percent of the human population has some form of lactose intolerance. As part of your…

A: We want to find the 90% confidence interval

Q: A smart phone manufacturer wants to find out what proportion of its customers are dissatisfied with…

A: Given that - A smart phone manufacturer wants to find out what proportion of its customers are…

Q: a survey of 3088 adults aged 57 through 85​ years, it was found that 87.1​% of them used at least…

A: The formula for computing confidence interval is,  n is the sample size and P is the proportion.

Q: confidence inferval for the actual percentage of students who want to pursue a college course.…

A: here from given  n = sample size  = 600 x= no of student expressed interest to purchase a college…

Q: A survey was conducted to determine if adults in the U.S., France, and Germany believed humans…

A: The objective of this question is to construct 99% confidence intervals for the proportion of adults…

Q: A May 2000 Gallup poll found that 38% of a random sample of 1012 adults in the United States said…

A: (a)   Obtain the 96% confidence interval to estimate the true proportion of all U. S. adults who…

Q: . How many of the 3335 subjects used at least one prescription​ medication? b. Construct a​ 90%…

A: n = 3335 p = 0.804

Q: In a random sample of 850​ Americans, 385 reported that they work two jobs. Which of the following…

A: The known values are, The sample proportion is,

Q: 2. To estimate how often someone runs a red light in Cyber City, a student watched traffic for a…

A:

Q: In a random sample of 1003 US adults, 32% said that national identity is strongly tied to birth…

A: It is given that, 32% of the 1003 adults said that national identity is strongly tied to birth…

Q: In a survey of 3110 adults aged 57 through 85 years, it was found that 87.9% of them used at least…

A:

Q: In a survey of 1400 people, 75% indicated that they listened to their favorite radio station because…

A: In statistical inference there are two branches-1)hypothesis testing and 2)Estimation In estimation…

Q: In a survey of 3015 adults aged 57 through 85 years, it was found that 85.6% of them used at least…

A:

Q: A Gallup Youth Survey in 2001 found that of 501 randomly selected teenagers in the U.S., 271 of them…

A: Given Total number of teenagers selected = 501Number of teenagers said who get along with their…

Q: a survey of 1083 people, 585 answered "yes" to a particular question. Construct a 90% confidence…

A:

Q: What proportion of the sample reported that they had been cyberbullied?

A: Givensample size(n)=14795No.of respondents say yes they had been cyberbullied(x1) = 2219No.of…

Q: The figure to the right shows the results of a survey in which 1005 adults from Country​ A, 1023…

A: From the provided information, Sample size of Country B (n) = 1023 Sample proportion (p̂) = 0.22…

Q: g to recent​ study, 160 of 480 CEOs in a certain country are extremely concerned about Cyber​…

A: (a) Total sample = 480 People who are extremely concerned about Cyber​ threats = 160 The value of z…

Q: In a Harvard School of Public Health survey, 2105 of 10,904 randomly selected U.S. college students…

A: Given data is appropriate for testing of hypothesis. Because it is a large sample test for single…

Q: In a survey of 3473 adults aged 57 through 85​ years, it was found that 84.6% of them used at least…

A:

Q: The branch manager of an outlet store​ (Store 1) of a nationwide chain of pet supply stores wants to…

A: Comment: As per the our company guidelines we are supposed to answer only three subparts. Kindly…

Q: A publishing company is studying the sales of various franchises in their chain of stores. A…

A: We are given confidence intervals for the population mean daily sales at 90%, 95%, 97% and 99%…

Q: In a survey of 2480 golfers, 15% said they were left-handed. The survey's margin of error was 3%.…

A: Sample size(n)=2480sampl proportion(p^)=0.15Margin of error(E)=0.03

Q: In describing the findings of a 2010 Public ReligionResearch Institute poll, the researchers…

A: Margin of error (E)= Z * SE   As the confidence interval increases z-value also increases. Example:…

Q: In a survey of 1000 randomly selected adults in the US, participants were asked what their most…

A:

Q: A restaurant owner, who owns fast food restaurants throughout Arkansas, Texas, and Oklahoma is…

A: Givensample size(n)=200x=118sample proportion(p^)=xn=118200=0.59confidence level=99%

Q: In a survey of 3332 adults aged 57 through 85​ years, it was found that 80.7​% of them used at least…

A:

Q: In a survey of 1,626,773 U.S. adults, 49,311 personally identified as lesbian, gay, bisexual, or…

A:

Q: nd tattoos were big personal grooming red​ flags?  b. Construct a​ 99% confidence interval estimate…

A:

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.