The P-value for a hypothesis test is shown. Use the P-value to decide whether to reject Ho when the level of significance is (a) α=0.01, (b) a= 0.05, and (c) α=0.10. P=0.0398 **** (a) Do you reject or fail to reject Ho at the 0.01 level of significance? O A. Reject Ho because the P-value, 0.0398, is less than α = 0.01. OB. Fail to reject Ho because the P-value, 0.0398, is greater than a = 0.01. OC. Fail to reject Ho because the P-value, 0.0398, is less than a = 0.01. OD. Reject Ho because the P-value, 0.0398, is greater than α=0.01.

The P-value for a hypothesis test is shown. Use the P-value to decide whether to reject Ho when the level of significance is (a) α=0.01, (b) a= 0.05, and (c) α=0.10. P=0.0398 **** (a) Do you reject or fail to reject Ho at the 0.01 level of significance? O A. Reject Ho because the P-value, 0.0398, is less than α = 0.01. OB. Fail to reject Ho because the P-value, 0.0398, is greater than a = 0.01. OC. Fail to reject Ho because the P-value, 0.0398, is less than a = 0.01. OD. Reject Ho because the P-value, 0.0398, is greater than α=0.01.

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Test the claim that the proportion of men who own cats is smaller than 90% at the 0.01 significance level. The null and alternative hypothesis would be: Ho: µ 0.9 Ho:p 0.9 Ho:µ = 0.9 Họ:p H1:µ > 0.9 H1:p 0.9 Hị: µ < 0.9 H1:µ + 0.9 H1:p# 0.9 0.9 The test is: two-tailed left-tailed right-tailed Based on a sample of 200 people, 87% owned cats The test statistic is: (to 2 decimals) The critical value is: (to 2 decimals)
Z-Test Z-Test Use the calculator displays to the right to make a decision to reject or fail to reject the null hypothesis at a significance level of α = 0.05. Inpt: Data Statsu #70 Ho:70 o:3.75 x:68.75 In:40 H:Ho Ho Ho Calculate Draw Choose the correct answer below. O A. Since the P-value is greater than x, fail to reject the null hypothesis. OB. Since the P-value is greater than x, reject the null hypothesis. OC. Since the P-value is less than x, reject the null hypothesis. O D. Since the P-value is less than x, fail to reject the null hypothesis. z=2.10818511 p=0.03501498 x = 68.75 n=40
Test the claim that the mean GPA of Orange Coast students is smaller than the mean GPA of Coastline students at the 0.01 significance level. The null and alternative hypothesis would be: Ho:Po = Pc Ho:Po > Pc Ho:µ0 µc H1: Ho Pc H1:µo + HC The test is: two-tailed left-tailed right-tailed The sample consisted of 55 Orange Coast students, with a sample mean GPA of 3.46 and a standard deviation of 0.08, and 55 Coastline students, with a sample mean GPA of 3.49 and a standard deviation of 0.07. The test statistic is: (to 2 decimals) The p-value is: (to 2 decimals) Based on this we: O Fail to reject the null hypothesis Reject the null hypothesis
Test the claim that the mean GPA of night students is smaller than the mean GPA of day students at the 0.025 significance level. The null and alternative hypothesis would be: Ho: HN S HD Ho:pN 2 PD Ho:PN = PD Ho:UN = HD Ho: PN HD H:PN PD H1: µN Next Question hp
Test the claim that the mean GPA of night students is larger than 2.4 at the 0.025 significance level. The null and alternative hypothesis would be: Ho: µ = — 2.4 Но:р 2.4 Н: + 2.4 H:p> 0.6 H:д> 2.4 Hi:p #0.6 Hi:p < 0.6 Н:р < 2.4 The test is: left-tailed two-tailed right-tailed Based on a sample of 65 people, the sample mean GPA was 2.41 with a standard deviation of 0.03 The test statistic is: (to 2 decimals) The p-value is: (to 2 decimals) Based on this we: O Reject the null hypothesis O Fail to reject the null hypothesis
State the Result: A hypothesis test was conducted at the alpha = 0.01 level of significance. The test resulted in a p-value of 0.044.
K The P-value for a hypothesis test is shown. Use the P-value to decide whether to reject Ho when the level of significance is (a) a= 0.01, (b) a = 0.05, and (c) a = 0.10. P=0.0647 .. (a) Do you reject or fail to reject Ho at the 0.01 level of significance? OA. Reject Ho because the P-value, 0.0647, is greater than α=0.01. O B. Fail to reject Ho because the P-value, 0.0647, is less than α = 0.01. O C. Fail to reject Ho because the P-value, 0.0647, is greater than a = 0.01. OD. Reject Ho because the P-value, 0.0647, is less than a = 0.01. (b) Do you reject or fail to reject Ho at the 0.05 level of significance? OA. Fail to reject Ho because the P-value, 0.0647, is greater than α=0.05. OB. Reject Ho because the P-value, 0.0647, is greater than a = 0.05. OC. Reject Ho because the P-value, 0.0647, is less than a = 0.05. O D. Fail to reject Ho because the P-value, 0.0647, is less than a = 0.05. (c) Do you reject or fail to reject Ho at the 0.10 level of significance? 1
Dentists A toothpaste company wants to declare in an ad that more than 80% of dentists recommend their toothpaste. The company performs a hypothesis test at the α = 0.05 significance level to test their claim. The company samples 800 dentists. Of these, 653 recommend their toothpaste. Let p represent the population proportion of dentists that recommend their toothpaste. b.Calculate the z or t statistic. (Do not use continuity correction. Round final answer to 4 decimal places) Statistic: c. Find the p-value. (Do not use continuity correction. Round final answer to 4 decimal places) p-value:
Can you help me with this part?
Test the daim that the proportion of men who own cats is significan tly different than the proportion of women who own cats at the 0.02 significance level. The null and alternative hypothesis would be: Ho:PM = PF Ho:HM PF Ho:PM µp H1:µM PF H1:µM + HF The test is left-tailed two-tailed right-tailed Based on a sample of 80 men, 40% owned cats Based on a sample of 20 women, 50% owned cats positive Critical Value = [three decimal accuracy] Test Statistic = [three decimal accuracy] Based on this we: O Reject the null hypothesis O Fail to reject the null hypothesis
Test the claim that the proportion of people who own cats is larger than 20% at the 0.005 significance level. The null and alternative hypothesis would be: H2:p = 0.2 Họ:p 2 0.2 H9:p 0.2 H9:p = 0.2 Hg: u 0.2 H1: u 0.2 The test is: left-tailed two-tailed right-tailed Based on a sample of 300 people, 24% owned cats The test statistic is: (to 2 decimals) The p-value is: (to 2 decimals) Based on this we: O Reject the null hypothesis O Fail to reject the null hypothesis
True or False? If we reject the null hypothesis at a significance level of α = .05, then we also reject the null hypothesis at a significance level of α = .01. If we fail to reject the null hypothesis at a significance level of α = .01, then we also fail to reject the null hypothesis at a significance level of α = .05. If we fail to reject the null hypothesis at a significance level of α = .05, then we also fail to reject the null hypothesis at a significance level of α = .01.