Perform the test of hypothesis on the following scenarios.A brand of powdered milk is advertised as having a net weight of 250 grams. A curious consumer obtained the net weight of 10 randomly selected cans. The values obtained are256, 248, 242, 245, 246, 248, 250, 255, 243, and 249 grams. Is there reason to believe that the average net weight of the powdered milk cans is less than 250 grams at 10% level of significance? Assume the net weight is normally distributed with unknown population variance.Note: pls follow the given steps in the photo attached Please follow the stepsSolution:Given:Methodnx (Sample Mean)s (Sample SD)Proposedn₁ = 15S₁ = 4.98X₁ = 24.27X₂ = 20.93Existingn₂ = 15$2 = 155.05*** Compute first the mean and standard deviation using the given data in theproblem. (Recall our previous lesson on how to get the mean and standard deviation).Step 1: Form the null and alternative hypothesis.Ho: The E-learning method is as effective as the traditional method of teaching; or μ₁ =μ₂.Ha: The E-learning method is more effective than the traditional method of teaching; orμε > Ma.Step 2: A one-tailed t-test must be used since n<30 and the given a = 5%. Thedegree of freedom is df = n₁ + n2-2=15+15-2 = 28Step 3: A one-tailed test at a = 5% would give c = 1.701 using the t-table with adegree of freedom equals to 28.71PageLear IvIUuure линиStep 4: Computing for the t-score, we have:t=*= √nt = 12-10√12 = 1.7320.4Step 5: Since t < c, or the computed t-score is in the region of Ho, we accept Ho.Conclusion: There is no significant difference between the mean serum of thesample group and that of the population.1 tonahing method is more effective

The question is about hypo. testing for a popl. mean Given : Popl. mean of net weight of milk cans (…

Answered: Perform the test of hypothesis on the…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Question

Perform the test of hypothesis on the following scenarios. A brand of powdered milk is advertised as having a net weight of 250 grams. A curious consumer obtained the net weight of 10 randomly selected cans. The values obtained are 256, 248, 242, 245, 246, 248, 250, 255, 243, and 249 grams. Is there reason to believe that the average net weight of the powdered milk cans is less than 250 grams at 10% level of significance? Assume the net weight is normally distributed with unknown population variance. Note: pls follow the given steps in the photo attached

Please follow the steps
Solution:
Given:
Method
n
x (Sample Mean)
s (Sample SD)
Proposed
n₁ = 15
S₁ = 4.98
X₁ = 24.27
X₂ = 20.93
Existing
n₂ = 15
$2 = 155.05
*** Compute first the mean and standard deviation using the given data in the
problem. (Recall our previous lesson on how to get the mean and standard deviation).
Step 1: Form the null and alternative hypothesis.
Ho: The E-learning method is as effective as the traditional method of teaching; or μ₁ =
μ₂.
Ha: The E-learning method is more effective than the traditional method of teaching; or
με > Ma.
Step 2: A one-tailed t-test must be used since n<30 and the given a = 5%. The
degree of freedom is df = n₁ + n2-2=15+15-2 = 28
Step 3: A one-tailed test at a = 5% would give c = 1.701 using the t-table with a
degree of freedom equals to 28.
71Page
Lear IvIUuure лини
Step 4: Computing for the t-score, we have:
t=*= √n
t = 12-10√12 = 1.732
0.4
Step 5: Since t < c, or the computed t-score is in the region of Ho, we accept Ho.
Conclusion: There is no significant difference between the mean serum of the
sample group and that of the population.
1 tonahing method is more effective

Features Features Normal distribution is characterized by two parameters, mean (µ) and standard deviation (σ). When graphed, the mean represents the center of the bell curve and the graph is perfectly symmetric about the center. The mean, median, and mode are all equal for a normal distribution. The standard deviation measures the data's spread from the center. The higher the standard deviation, the more the data is spread out and the flatter the bell curve looks. Variance is another commonly used measure of the spread of the distribution and is equal to the square of the standard deviation.

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