O Lulion laflace Luma fanm of LiS Con t dt G(4) = If L[fla)] = F(S) thin L[ fl4] = (1," " a (tive intig in in () If L[ fA)] = FIS) thin L{u(t-a) } = () u (t-a) unit 6 tab funete in an Page Break fie have , (-1)° d? F(S) = L(Cos & } and %3D Li Cud at ) :- a Li Cos £ } = (-1
O Lulion laflace Luma fanm of LiS Con t dt G(4) = If L[fla)] = F(S) thin L[ fl4] = (1," " a (tive intig in in () If L[ fA)] = FIS) thin L{u(t-a) } = () u (t-a) unit 6 tab funete in an Page Break fie have , (-1)° d? F(S) = L(Cos & } and %3D Li Cud at ) :- a Li Cos £ } = (-1
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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(7) Can you translate this into words? Please explain the solution in detail because I'm going to make a script out of it.
![o lulion 7
laplace tuna fanm of
G(4) =
1
If
L[ fle)] =
F(S)
thin
don [FIS)]
a tve intg
If
L[ fld)] = FIS)
FIS)
95
L{ u(t-a) }
%3D
u (t-a)
unit 6 tep funedin
is
an
Page Break
fie have,
frt)
[ F(S)]
Cod t
Cthere
F(S) = L( Cos £ }
and
s'+ 1
Li Cod at )](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fdde3ae2a-42ac-433e-9f60-e7d93b0f2f12%2Fd470c526-26ed-4248-968d-f4a26d992989%2Fcrnqjm_processed.jpeg&w=3840&q=75)
Transcribed Image Text:o lulion 7
laplace tuna fanm of
G(4) =
1
If
L[ fle)] =
F(S)
thin
don [FIS)]
a tve intg
If
L[ fld)] = FIS)
FIS)
95
L{ u(t-a) }
%3D
u (t-a)
unit 6 tep funedin
is
an
Page Break
fie have,
frt)
[ F(S)]
Cod t
Cthere
F(S) = L( Cos £ }
and
s'+ 1
Li Cod at )
![Li t Cod t } = (-tỷ d
ds
SP
[
1 - s?
ds
(s+ 13° (-R8) - (1-s³) a (s+1) (2 s)
(s4 1) T
(s'41) [ -2s (s%v - 1S ( 1-s°)]
(s 1)+
-Rs - R5 - †S + +s³
%3D
F(S)
Hence ,
F(S)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fdde3ae2a-42ac-433e-9f60-e7d93b0f2f12%2Fd470c526-26ed-4248-968d-f4a26d992989%2Fhzx0e3d_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Li t Cod t } = (-tỷ d
ds
SP
[
1 - s?
ds
(s+ 13° (-R8) - (1-s³) a (s+1) (2 s)
(s4 1) T
(s'41) [ -2s (s%v - 1S ( 1-s°)]
(s 1)+
-Rs - R5 - †S + +s³
%3D
F(S)
Hence ,
F(S)
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