O 57% Listed in the data table are amounts of strontium-90 (in millibecquerels, or mBq, per gram of calcium) in a simple random sample of baby teeth obtained from residents in two cities. Assume that the two samples are independent simple random samples selected from normally distributed populations. Do not assume that the population standard deviations are equal. Use a 0.01 significance level to test the claim that the mean amount of strontium-90 from city #1 residents is greater than the mean amount from city #2 residents. 9% Click the icon to view the data table of strontium-90 amounts. 78% What are the null and alternative hypotheses? Assume that population 1 consists of amounts from city #1 levels and population 2 consists of amounts from city #2. O A. Ho: H1 SH2 77% O B. Ho: H1 =P2 H #2 H: Hq> H2 O C. Ho H1=H2 H: H1> H2 21% O D. Ho: H1 #H2 H1: H> H2 19% The test statistic is (Round to two decimal places as needed.) The P-value is (Round to three decimal places as needed.) 29% State the conclusion for the test. O A. Fail to reject the null hypothesis. There is not sufficient evidence to support the claim that the mean amount of strontium-90 from city #1 residents is greater. 52% O B. Reject the null hypothesis. There is sufficient evidence to support the claim that the mean amount of strontium-90 from city #1 residents is greater. O C. Reject the null hypothesis. There is not sufficient evidence to support the claim that the mean amount of strontium-90 from city #1 residents is greater. O D. Fail to reject the null hypothesis. There is sufficient evidence to support the claim that the mean amount of strontium-90 from city #1 residents is greater. Click to select your answer(s).
O 57% Listed in the data table are amounts of strontium-90 (in millibecquerels, or mBq, per gram of calcium) in a simple random sample of baby teeth obtained from residents in two cities. Assume that the two samples are independent simple random samples selected from normally distributed populations. Do not assume that the population standard deviations are equal. Use a 0.01 significance level to test the claim that the mean amount of strontium-90 from city #1 residents is greater than the mean amount from city #2 residents. 9% Click the icon to view the data table of strontium-90 amounts. 78% What are the null and alternative hypotheses? Assume that population 1 consists of amounts from city #1 levels and population 2 consists of amounts from city #2. O A. Ho: H1 SH2 77% O B. Ho: H1 =P2 H #2 H: Hq> H2 O C. Ho H1=H2 H: H1> H2 21% O D. Ho: H1 #H2 H1: H> H2 19% The test statistic is (Round to two decimal places as needed.) The P-value is (Round to three decimal places as needed.) 29% State the conclusion for the test. O A. Fail to reject the null hypothesis. There is not sufficient evidence to support the claim that the mean amount of strontium-90 from city #1 residents is greater. 52% O B. Reject the null hypothesis. There is sufficient evidence to support the claim that the mean amount of strontium-90 from city #1 residents is greater. O C. Reject the null hypothesis. There is not sufficient evidence to support the claim that the mean amount of strontium-90 from city #1 residents is greater. O D. Fail to reject the null hypothesis. There is sufficient evidence to support the claim that the mean amount of strontium-90 from city #1 residents is greater. Click to select your answer(s).
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
Transcribed Image Text:More Info
and
City #1
108
86
121
117
101
104
213
105
290
100
283
145
City #2
117
78
100
85
85
107
110
111
111
133
101
209
as
suf
bunt of
evid
ontium-
cient
Print
Done
strontiu
fficiel
of stron
Transcribed Image Text:57%
Listed in the data table are amounts of strontium-90 (in millibecquerels, or mBq, per gram of calcium) in a simple random sample of baby teeth obtained from residents
in two cities. Assume that the two samples are independent simple random samples selected from normally distributed populations. Do not assume that the population
standard deviations are equal. Use a 0.01 significance level to test the claim that the mean amount of strontium-90 from city #1 residents is greater than the mean
amount from city #2 residents.
Click the icon to view the data table of strontium-90 amounts.
9%
78%
What are the null and alternative hypotheses? Assume that population 1 consists of amounts from city #1 levels and population 2 consists of amounts from city #2.
77%
O A. Ho H1 SH2
Hq: H1> H2
O B. Ho: H1 =H2
OC. Ho H1 =H2
21%
O D. Ho: H1 #H2
H1: 4 > H2
H:H1>H2
19%
The test statistic is
(Round to two decimal places as needed.)
The P-value is
(Round to three decimal places as needed.)
29%
State the conclusion for the test.
52%
O A. Fail to reject the null hypothesis. There is not sufficient evidence to support the claim that the mean amount of strontium-90 from city #1 residents is greater.
O B. Reject the null hypothesis. There is sufficient evidence to support the claim that the mean amount of strontium-90 from city #1 residents is greater.
O C. Reject the null hypothesis. There is not sufficient evidence to support the claim that the mean amount of strontium-90 from city #1 residents is greater.
O D. Fail to reject the null hypothesis. There is sufficient evidence to support the claim that the mean amount of strontium-90 from city #1 residents is greater.
Click to select your answer(s).
P Pearson
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4/26/2021
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MENU/L READER/4 FUNC. AUTO/ INPUT/EXIT
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