The image shows a multiple-choice question with four answer options. The question prompt is not visible, but the focus is on selecting the correct value in cubic centimeters (cm³).Here are the answer options:1. ○ 19.0 cm³2. ○ 6.0 cm³3. ○ 7.0 cm³4. ○ 13.0 cm³Each answer option is accompanied by a radio button, indicating that the respondent can select only one of the options. There are no graphs or diagrams accompanying this text. **Mass vs. Volume Graph Analysis****Examine the graph of mass vs. volume of a substance below and answer the following question.****How much does the volume (cm³) of the substance increase when the mass increases from 16.0 g to 35.0 g?****Graph Explanation:**- The graph represents the relationship between mass (in grams, g) and volume (in cubic centimeters, cm³) of a substance.- The x-axis (horizontal axis) denotes the volume of the substance in cm³ ranging from 0 to 15.- The y-axis (vertical axis) denotes the mass of the substance in grams (g) ranging from 0 to 40.- The data points plotted on the graph indicate that there is a linear relationship between volume and mass, which implies that the substance in question has a constant density.- The line of best fit runs through the data points and validates the linear relationship between mass and volume.**Answer Calculation:**To determine how much the volume increases when the mass increases from 16.0 g to 35.0 g, follow these steps on the graph:1. Locate 16.0 g on the y-axis and find the corresponding volume on the x-axis.2. Do the same for 35.0 g on the y-axis.3. Determine the difference in the x-axis values (volumes) corresponding to these masses.For 16.0 g:- The corresponding volume on the x-axis is approximately 7.5 cm³.For 35.0 g:- The corresponding volume on the x-axis is approximately 15 cm³.**Volume Increase:**- The volume increases from 7.5 cm³ to 15 cm³.- The increase in volume is: 15 cm³ - 7.5 cm³ = 7.5 cm³.Therefore, when the mass increases from 16.0 g to 35.0 g, the volume of the substance increases by 7.5 cm³.

Answered: Image /qna-images/answer/b2c822eb-1876-4474-875e-923ffe30e7eb.jpg

Answered: O 19.0 cm³ 6.0 cm³ O 7.0 cm³ O 13.0 cm³…

Science

Chemistry

O 19.0 cm³ 6.0 cm³ O 7.0 cm³ O 13.0 cm³ O

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Similar questions

Solutions of sodium carbonate and silver-nitrate react to form solid silver carbonate and a solution of sodium nitrate. A solution containing 8.00 g of sodium carbonate is mixed with one containing 4.00 g of silver nitrate. After the reaction is complete, the solutions are evaporated to dryness, leaving a mixture of salts. How many grams of each of the following compounds are present after the reaction is complete? sodium carbonate 1.52 silver nitrate 0 X 9 sodium nitrate 12.84 ✓ q silver carbonate 6.48 X g X 9 D
0.400 ✓ STARTING AMOUNT 0.400 L X 0.350 mol KBr 1 L X 16.7 g KBr 0.350 mol KBr ✓ What is the mass in grams of KBr in 0.400 = ADD FACTOR x( ) X 0.400 0.140 16.7 5.47 16.7 mol KBr g KBr mL DELETE X A 39.10 1 6.022 × 1023 1.18 × 10-³ M KBr L L of a 0.350 M solution? ANSWER 0.350 136 7.09 × 102⁰ 9.60 × 10-³ g KBr RESET 3 8.43 × 10²² g KBr/mol 119
Gibberellic acid, C19H22O6, is used to promote plant growth, particularly in seedlings. How many molecules of gibberellic acid are contained in 0.250 lbs of this compound? 5.92 x 1023 molecules 346 molecules 1.00 molecule 3.47 x 1023 molecules 1.97 x 1023 molecules
You are given a 15.0 g mixture. You find out that the mixture contains 3.55 g salt, 4.78 g sand and the rest is Iron. According to these data, what is the percent of iron in the mixture? O 55.5% O 6.67% O 44.5% 15,0%
0.10 M formic acid (HCHO₂) Ka = 1.8 x 104 0.10 M sodium formate (NaCHO₂) 0.10 M acetic acid (HC2H302) Ka = 1.8 x 10¹5 0.10 M sodium acetate (Na C₂H30₂) 0.10 M carbonic acid (H₂CO3) Ka = 4.3 x 107 0.10 M sodium bicarbonate (NaHCO3) 0.10 M KOH 0.10 M HCI 0.10 M boric acid (H3BO3) Ka = 5.8 x 10-10 0.10 M sodium borate (NaH₂BO3) 4. Which reagents listed above should be mixed to result in a buffer of about pH 6-8?
A chemist adds 55.0 mL of a 1.27M sodium thiosulfate (Na₂S₂O3) solution to a reaction flask. Calculate the mass in grams of sodium thiosulfate the chemist has added to the flask. Round your answer to 3 significant digits. X S 6 0
Multiply or divide the following measurements. Be sure each answer you enter contains the corr 78.08 mol L X 34. L = mol 686.1 mol 0.64 L 422.78 g 79.260 mL 11 || 0 mol L 0- mL x10 X G
Suppose 4.20 g of iron(II) chloride is dissolved in 300. mL of a 75.0 m M aqueous solution of silver nitrate. Calculate the final molarity of chloride anion in the solution. You can assume the volume of the solution doesn't change when the iron (II) chloride is dissolved in it. Be sure your answer has the correct number of significant digits. M x10
What is the volume (in mL) of isopropanol that contains 7.23 × 1022 molecules of isopropanol? The density of isopropanol is 0.786 g/mL and its molar mass is 60.10 g/mol.
Which piece of equipment would you use to measure 7.10 mL of CuSO4 (aq)?
A chemist adds 380.0 mL of a 0.00694 mmol/L calcium sulfate (CaSO4) solution to a reaction flask. Calculate the mass in milligrams of calcium sulfate the chemist has added to the flask. Round your answer to 3 significant digits. 1mg 0.9 X G
A chemist adds 95.0 mL of a 0.26M aluminum sulfate (Al₂(SO4)3): solution to a reaction flask. Calculate the mass in grams of aluminum sulfate the chemist has added to the flask. Round your answer to 2 significant digits. 08 0 x10 X