Nuclear Binding Energy II Calculate the binding energy per nucleon for the nucleus. (Atomic masses: iron-56 = 55.9349 amu; hydrogen-1 = 1.0078 amu; mass of neutron = 1.0087 amu) We must first calculate the mass defect (Am) for 56Fe. Since atomic masses (which include the electrons) are given, we must decide how to account for the electron mass: 55.9349 = mass of Fe atom = mass of nucleus + 26 me 1.0078 = mass of H atom = mass of nucleus + me Thus, since a 56Fe nucleus is "synthesized" from 26 protons and 30 neutrons, we see that Am = (55.9349 - 26 me) - [26(1.0078 - me) + 30(1.0087)]. Solve for Am. Am = -0.5289 amu Submit What is the energy change? AE = -7.9x10^-11 J/nucleus Submit What is the binding energy (BE) per nucleon? BE per nucleon = X MeV/nucleon

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INTERACTIVE EXAMPLE
Nuclear Binding Energy II
Calculate the binding energy per nucleon for the nucleus. (Atomic masses: iron-56 = 55.9349 amu; hydrogen-1 = 1.0078 amu; mass of neutron = 1.0087 amu)
We must first calculate the mass defect (Am) for 56F.. Since atomic masses (which include the electrons) are given, we must decide how to account for the electron mass:
55.9349 = mass of Fe atom = mass of nucleus + 26 me
1.0078 = mass of H atom mass of nucleus + me
Thus, since a 56Fe nucleus is "synthesized" from 26 protons and 30 neutrons, we see that Am = (55.9349 26 m.) - [26(1.0078 - me) + 30(1.0087)].
Solve for Am.
Am =
-0.5289
amu
Submit
What is the energy change?
AE =
-7.9x10A-11
J/nucleus
Submit
What is the binding energy (BE) per nucleon?
BE per nucleon =
X MeV/nucleon
Transcribed Image Text:INTERACTIVE EXAMPLE Nuclear Binding Energy II Calculate the binding energy per nucleon for the nucleus. (Atomic masses: iron-56 = 55.9349 amu; hydrogen-1 = 1.0078 amu; mass of neutron = 1.0087 amu) We must first calculate the mass defect (Am) for 56F.. Since atomic masses (which include the electrons) are given, we must decide how to account for the electron mass: 55.9349 = mass of Fe atom = mass of nucleus + 26 me 1.0078 = mass of H atom mass of nucleus + me Thus, since a 56Fe nucleus is "synthesized" from 26 protons and 30 neutrons, we see that Am = (55.9349 26 m.) - [26(1.0078 - me) + 30(1.0087)]. Solve for Am. Am = -0.5289 amu Submit What is the energy change? AE = -7.9x10A-11 J/nucleus Submit What is the binding energy (BE) per nucleon? BE per nucleon = X MeV/nucleon
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