Calculate the binding energy per nucleon for the 2Fe nucleus. (Atomic masses: iron-56 = 55.9349 amu; hydrogen-1 = 1.0078 amu; mass of neutron = 1.0087 amu) HOW DO WE GET THERE? We must first calculate the mass defect (Am) for 56Fe. Since atomic masses (which include the electrons) are given, we must decide how to account for the electre 55.9349 = mass of 6 Fe atom = mass of nucleus + 26 m, 1.0078 = mass of H atom mass of nucleus + m. Thus, since a 56FE nucleus is "synthesized" from 26 protons and 30 neutrons, we see that Am = (55.9349 - 26 me) - [26(1.0078 - me) + 30(1.0087)]. Solve for Am

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Chapter1: Chemical Foundations
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Calculate the binding energy per nucleon for the
Fe
nucleus. (Atomic masses: iron-56 = 55.9349 amu; hydrogen-1 = 1.0078 amu; mass of neutron = 1.0087 amu)
HOW DO WE GET THERE?
We must first calculate the mass defect (Am) for 56Fe. Since atomic masses (which include the electrons) are given, we must decide how to account for the electron mass:
55.9349 = mass of Fe atom = mass of nucleus + 26 m,
1.0078 = mass of H atom = mass of nucleus + m.
Thus, since a 56Fe nucleus is "synthesized" from 26 protons and 30 neutrons, we see that Am = (55.9349 – 26 me) - [26(1.0078 - me) + 30(1.0087)].
Solve for Am.
Am =
amu
Check
Next
(1 of 3)
Transcribed Image Text:Calculate the binding energy per nucleon for the Fe nucleus. (Atomic masses: iron-56 = 55.9349 amu; hydrogen-1 = 1.0078 amu; mass of neutron = 1.0087 amu) HOW DO WE GET THERE? We must first calculate the mass defect (Am) for 56Fe. Since atomic masses (which include the electrons) are given, we must decide how to account for the electron mass: 55.9349 = mass of Fe atom = mass of nucleus + 26 m, 1.0078 = mass of H atom = mass of nucleus + m. Thus, since a 56Fe nucleus is "synthesized" from 26 protons and 30 neutrons, we see that Am = (55.9349 – 26 me) - [26(1.0078 - me) + 30(1.0087)]. Solve for Am. Am = amu Check Next (1 of 3)
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