Calculate the binding energy per nucleon for the Fe nucleus. (Atomic masses: iron-56 = 55.9349 amu; hydrogen-1 = 1.0078 amu; mass of neutron = 1.0087 amu) HOW DO WE GET THERE? We must first calculate the mass defect (Am) for 56Fe. Since atomic masses (which include the electrons) are given, we must decide how to account for the electron mass: 55.9349 = mass of Fe atom = mass of nucleus + 26 me 1.0078 = mass of H atom = mass of nucleus + me Thus, since a 56Fe nucleus is "synthesized" from 26 protons and 30 neutrons, we see that Am = (55.9349 - 26 me) - [26(1.0078 - me) + 30(1.0087)]. Solve for Am. Am = 0,5289 x amu Recheck Next (1 of 3)

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Calculate the binding energy per nucleon for the
26 Fe
nucleus. (Atomic masses: iron-56 = 55.9349 amu; hydrogen-1 = 1.0078 amu; mass of neutron = 1.0087 amu)
HOW DO WE GET THERE?
We must first calculate the mass defect (Am) for 56Fe. Since atomic masses (which include the electrons) are given, we must decide how to account for the electron mass:
56
55.9349 = mass of Fe atom = mass of nucleus + 26 m.
1.0078 = mass of H atom = mass of nucleus + me
Thus, since a 56Fe nucleus is "synthesized" from 26 protons and 30 neutrons, we see that Am = (55.9349 - 26 me) - [26(1.0078 - me) + 30(1.0087)].
Solve for Am.
Am = 0.5289
amu
Recheck
Next
(1 of 3)
2nd attempt
Transcribed Image Text:Calculate the binding energy per nucleon for the 26 Fe nucleus. (Atomic masses: iron-56 = 55.9349 amu; hydrogen-1 = 1.0078 amu; mass of neutron = 1.0087 amu) HOW DO WE GET THERE? We must first calculate the mass defect (Am) for 56Fe. Since atomic masses (which include the electrons) are given, we must decide how to account for the electron mass: 56 55.9349 = mass of Fe atom = mass of nucleus + 26 m. 1.0078 = mass of H atom = mass of nucleus + me Thus, since a 56Fe nucleus is "synthesized" from 26 protons and 30 neutrons, we see that Am = (55.9349 - 26 me) - [26(1.0078 - me) + 30(1.0087)]. Solve for Am. Am = 0.5289 amu Recheck Next (1 of 3) 2nd attempt
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