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Note: As per policy, we can solve the first three subparts. Please resubmit the remaining part. Coefficient of performance of the refrigerator, COP = 5.5 The required power input, W = 0.6 kW Surrounding temperature, Ta = 25 o C = 25 + 273 = 298 K Condenser inlet condition, P = 1000 kPa and 60 oC Refrigerant = R134a   please solve part D only

Note: As per policy, we can solve the first three subparts. Please resubmit the remaining part. Coefficient of performance of the refrigerator, COP = 5.5 The required power input, W = 0.6 kW Surrounding temperature, Ta = 25 o C = 25 + 273 = 298 K Condenser inlet condition, P = 1000 kPa and 60 oC Refrigerant = R134a   please solve part D only

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Note: As per policy, we can solve the first three subparts. Please resubmit the remaining part.
Coefficient of performance of the refrigerator, COP = 5.5
The required power input, W = 0.6 kW
Surrounding temperature, Ta = 25
o C = 25 + 273 = 298 K
Condenser inlet condition, P = 1000 kPa and 60
oC
Refrigerant = R134a

 

please solve part D only

Surrounding 25°C Qrej Qrej P1 = 1000kPa Ti = 60°C 0.6kW a) b) You have just learned 2™d law of thermodynamics and wanted to test your understanding by investigating the refrigerator at your home. From catalogue, you figured that the coefficient of performance of the refrigerator is 5.5 and the required power input is 0.6kW. Energy is released from the refrigerator to the surrounding through metal coils (condenser) at the back of the refrigerator. You measured the surrounding temperature to be 25°C and assumed the refrigerator operated at steady state. a) Sketch the schematic of the refrigerator system b) Determine the rate of energy rejected from the coil to the surrounding in kW c) Determine the lowest theoretical temperature you can get inside the refrigerator in K d) If the R134a enters the condenser (see Fig b) at 1000kPa and 60°C and leaves as saturated liquid at the same pressure, find the mass flow rate of the refrigerant in the condenser coil in kg/s.
Transcribed Image Text:Surrounding 25°C Qrej Qrej P1 = 1000kPa Ti = 60°C 0.6kW a) b) You have just learned 2™d law of thermodynamics and wanted to test your understanding by investigating the refrigerator at your home. From catalogue, you figured that the coefficient of performance of the refrigerator is 5.5 and the required power input is 0.6kW. Energy is released from the refrigerator to the surrounding through metal coils (condenser) at the back of the refrigerator. You measured the surrounding temperature to be 25°C and assumed the refrigerator operated at steady state. a) Sketch the schematic of the refrigerator system b) Determine the rate of energy rejected from the coil to the surrounding in kW c) Determine the lowest theoretical temperature you can get inside the refrigerator in K d) If the R134a enters the condenser (see Fig b) at 1000kPa and 60°C and leaves as saturated liquid at the same pressure, find the mass flow rate of the refrigerant in the condenser coil in kg/s.
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