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ANSWER THE PROBLEM WITH COMPLETE SOLUTIONS. PLEASE WRITE LEGIBLY.

ANSWER THE PROBLEM WITH COMPLETE SOLUTIONS. PLEASE WRITE LEGIBLY.

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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ANSWER THE PROBLEM WITH COMPLETE SOLUTIONS. PLEASE WRITE LEGIBLY.
1. Consider a reheat-regenerative vapor power cycle with two feed water heaters, a closed feedwater heater and an open feedwater heater. Steam enters the first turbine at 8.0 MPa, 480 °C and expands to 0.7 MPa. The steam is reheated to 440 °C before entering the second turbine, where it expands to the condenser pressure of 0.008 MPa. Steam is extracted from the first turbine at 2 MPa and fed to the closed feedwater heater. Feedwater leaves the closed heater at 205 °C and 8.0 MPa, and condensate exits as saturated liquid at 2 MPa. The condensate is trapped into the open feedwater heater. Steam extracted from the second turbine at 0.3 MPa is also fed into the open feedwater heater, which operates at 0.3 MPa. The stream exiting the open feedwater heater is saturated liquid at 0.3 MPa. The net power output of the cycle is 100 MW. There is no stray heat transfer from any component to its surroundings. What is the enthalpy of steam at the steam trap discharge? a. 561.47 kJ/kg b 608.79 kJ/kg c. 908.79 kJ/kg d. 889.47 kJ/kg 2. Determine the mass fraction of bled steam entering the closed feed water heater (y'). a. 0.1833 b. 0.3318 c. 0.2215 d. 0.1522 3. the mass fraction of bled steam entering the open feed water heater (y"). a. 0.1904 b. 0.1094 c. 0.0941 d. 0.1409
Transcribed Image Text:1. Consider a reheat-regenerative vapor power cycle with two feed water heaters, a closed feedwater heater and an open feedwater heater. Steam enters the first turbine at 8.0 MPa, 480 °C and expands to 0.7 MPa. The steam is reheated to 440 °C before entering the second turbine, where it expands to the condenser pressure of 0.008 MPa. Steam is extracted from the first turbine at 2 MPa and fed to the closed feedwater heater. Feedwater leaves the closed heater at 205 °C and 8.0 MPa, and condensate exits as saturated liquid at 2 MPa. The condensate is trapped into the open feedwater heater. Steam extracted from the second turbine at 0.3 MPa is also fed into the open feedwater heater, which operates at 0.3 MPa. The stream exiting the open feedwater heater is saturated liquid at 0.3 MPa. The net power output of the cycle is 100 MW. There is no stray heat transfer from any component to its surroundings. What is the enthalpy of steam at the steam trap discharge? a. 561.47 kJ/kg b 608.79 kJ/kg c. 908.79 kJ/kg d. 889.47 kJ/kg 2. Determine the mass fraction of bled steam entering the closed feed water heater (y'). a. 0.1833 b. 0.3318 c. 0.2215 d. 0.1522 3. the mass fraction of bled steam entering the open feed water heater (y"). a. 0.1904 b. 0.1094 c. 0.0941 d. 0.1409
Schematic Diagram and T-s Diagram for Problem III. 7₁-4KPC T₁ = 480°C 4- 8.0 MPa 12 2.0 MPa 7.-2990 Closed heater 2.0MP 12 10 H Nue 0.3 MPM in Cond MURI MP vi...... 10 Pa 31 Trup h = 3348.4 kJ/kg s = 6.6586 kJ/kg-K h=2963.5 kJ/kg sf = 1.9922 kJ/kg-K sfg = 4.7158 kJ/kg-K sg = 6.708 kJ/kg-K h = 3353.3 kJ/kg s = 7.7571 kJ/kg-K h=3101.5 kJ/kg x = 0.9382 hf 173.88 kJ/kg hfg=2403.1 kJ/kg h7 = 173.88 kJ/kg h8 174.17 kJ/kg h9561.47 kJ/kg h10 569.73 kJ/kg h11882.4 kJ/kg h12908.79 kJ/kg 11 9 0.7 MPa 3 13 0.008 MPa 0.3 MPa 8 Pump At P = 8 MPa and T = 480 °C At P = 2 MPa and s= 6.6586 kJ/kg-K At P=0.7 MPa x = 0.9895 hf=697.22 kJ/kg hfg = 2066.3 kJ/kg At P = 0.7 MPa and T = 440 °C At P = 0.3 MPa and s = 7.7571 kJ/kg-K At P = 0.008 MPa and s= 7.7571 kJ/kg-K Given state point enthalpy: T₁ = 440°C
Transcribed Image Text:Schematic Diagram and T-s Diagram for Problem III. 7₁-4KPC T₁ = 480°C 4- 8.0 MPa 12 2.0 MPa 7.-2990 Closed heater 2.0MP 12 10 H Nue 0.3 MPM in Cond MURI MP vi...... 10 Pa 31 Trup h = 3348.4 kJ/kg s = 6.6586 kJ/kg-K h=2963.5 kJ/kg sf = 1.9922 kJ/kg-K sfg = 4.7158 kJ/kg-K sg = 6.708 kJ/kg-K h = 3353.3 kJ/kg s = 7.7571 kJ/kg-K h=3101.5 kJ/kg x = 0.9382 hf 173.88 kJ/kg hfg=2403.1 kJ/kg h7 = 173.88 kJ/kg h8 174.17 kJ/kg h9561.47 kJ/kg h10 569.73 kJ/kg h11882.4 kJ/kg h12908.79 kJ/kg 11 9 0.7 MPa 3 13 0.008 MPa 0.3 MPa 8 Pump At P = 8 MPa and T = 480 °C At P = 2 MPa and s= 6.6586 kJ/kg-K At P=0.7 MPa x = 0.9895 hf=697.22 kJ/kg hfg = 2066.3 kJ/kg At P = 0.7 MPa and T = 440 °C At P = 0.3 MPa and s = 7.7571 kJ/kg-K At P = 0.008 MPa and s= 7.7571 kJ/kg-K Given state point enthalpy: T₁ = 440°C
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