Not everyone pays the same price forthe same model of a car. The figureillustrates a normal distribution for theprices paid for a particular model of anew car. The mean is $18,000 and thestandard deviation is $2000.Use the 68-95-99.7 Rule to find thepercentage of buyers who paid less than$12,000.Number of Car Buyers99.7%-95%--68%1214 16 18 20 22 24Price of a Model of a New Car (Thousands)The percentage of buyers who paid less than $12,000 is %.

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A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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The figure illustrates a normal distribution for the prices paid for a particular model of a new car. The mean is $19,000 and the standard deviation is $500. Use the 68-95-99.7 Rule to find the percentage of buyers who paid between $17,500 and $19,000. Number of Car Buyers 99.7% 95% -68% 17.300 18.000 18.500 19.000 19,500 20,000 20.500 Price of a Model of a New Car What percentage of buyers paid between $17,500 and $19,000?
Solve the problem.Before a new phone system was installed, the amount a company spent on personal calls followed a normal distribution with an average of $400 per month and a standard deviation of $50 per month. Refer to such expenses as PCE's (personal call expenses). Find the point in the distribution above 4.5%. Round your answer to nearest hundredth
Not everyone pays the same price for the same model of a car. The figure illustrates a normal distribution for the prices paid for a particular model of a new car. The mean is $ 18 comma 000$18,000 and the standard deviation is $ 2000 Use the 68 - 95-99.7 68-95-99.7 Rule to find the percentage of buyers who paid more than $ 20 comma 000$20,000.
Determine whether the following graph can represent a variable with a nomal distribution. Explain your reasoning. If the graph appears to represent a normal distribution, estimate the mean and standard deviation. 10 15 20 25 30 Could the graph represent a variable with a normal distribution? Explain your reasoning. Select the correct choice below and, if necessary, fill in the answer boxes within your choice. O A. No, because the graph crosses the x-axis. O B. No, because the graph is skewed nght. O C. No, because the graph is skewed left. O D. Yes, the graph fulfills the properties of the normal distribution. The mean is approximately and the standard deviation is about- (Type whole numbers.) Clear all Final chec Help me solve this View an example Get more help -
K A commuter tallied the time to work for 200 days and found that it resembled a normal curve. The mean time was 50 minutes, and the standard deviation was 2 minutes. For the 200-work-day experiment, find the percent of time commuting to work less than 44 minutes. 44 Minutes to Commute to Office 1 46 48 68%- 95% 99/7% 50
It is commonly believed that the mean body temperature of a healthy adult is 98.6° F. You are not entirely convinced. You believe that it is higher than 98.6° F. The temperatures for 12 randomly selected healthy adults are shown below. Assume that the distribution of the population is normal. 100.1, 96.8, 98.7, 100, 99.1, 98.3, 97.5, 100.9, 99.1, 100, 98.1, 100.1 What can be concluded at the a = 0.05 level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Ho: ? Ha: Select an answer Select an answer c. The test statistic O Question Help: (please show your answer to 3 decimal places.) (Please show your answer to 4 decimal places.) d. The p-value = e. The p-value is a f. Based on this, we should Select an answer the null hypothesis. g. Thus, the final conclusion is that ... There is sufficient evidence to conclude that the population mean body temperature for healthy adults is higher than 98.6° F. There is not sufficient…
Using technology, find the range and standard deviation, round to one decimals place:The table below gives the number of hours spent watching TV last week by a sample of 24 children. 20 39 34 29 48 84 64 25 75 89 40 57 82 43 62 52 49 59 38 87 49 66 95 17 Range = 78 Standard Deviation = 22.6
(See photo) The data set on the left represents the annual rate of return (in percent) of eight randomly sampled bond mutual funds, and the data set on the right represents the annual rate of return (in percent) of eight randomly sampled stock mutual funds. What proportion of the observations is within one standard deviation of the mean for each data set?
The graph illustrates a normal distribution for the prices paid for a particular model of HD television. The mean price paid is $1600 and the standard deviation is $140.What is the approximate percentage of buyers who paid less than $1320? What is the approximate percentage of buyers who paid less than $1180?
Not everyone pays the same price for the same model of a car. The figure illustrates a normal distribution for the prices paid for a particular model of a new car. The mean is $22,000 and the standard deviation is $1000. Use the 68-95-99.7 Rule to find what percentage of buyers paid between $20,000 and $22,000. Number of Car Buyers 99.7% -95% 68% 19 20 24 Price of a Model of a New Car (Thousands) The percentage of buyers who paid between $20,000 and $22,000 is (Type an exact answer.) %. 25 C
Biology A biologist found the wingspans of a group of monary butterflies to be normally distributed with a mean of 52.2 mm and a standard deviation of 2.3 mm. What percent of the butterflies had a wingspan between 50 and 55 mm?

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