Not everyone pays the same price forthe same model of a car. The figureillustrates a normal distribution for theprices paid for a particular model of anew car. The mean is $23,000 and thestandard deviation is $2000.Use the 68-95-99.7 Rule to find whatpercentage of buyers paid between$19,000 and $27,000.Number of Car Buyers99,7%-95%-68%→17 19 2127Price of a Model of a New Car (Thousands)The percentage of buyers who paid between $19,000 and $27,000 is%.29

We have given the normal distribution for the prices paid for a particular model of a new carMean()…

Answered: Not everyone pays the same price for…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The figure illustrates a normal distribution for the prices paid for a particular model of a new car. The mean is $19,000 and the standard deviation is $500. Use the 68-95-99.7 Rule to find the percentage of buyers who paid between $17,500 and $19,000. Number of Car Buyers 99.7% 95% -68% 17.300 18.000 18.500 19.000 19,500 20,000 20.500 Price of a Model of a New Car What percentage of buyers paid between $17,500 and $19,000?
Find n. What is the value of the mean?
The estimated distribution (in millions) of the population by age in a certain country for the year 2015 is shown in the pie chart. Make a frequency distribution for the data. Then use the table to estimate the sample mean and the sample standard deviation of the data set. Use 70 as the midpoint for "65 years and over." I Under 4 years: 18.5 I 5-14 years: 39.7 O 15-19 years: 17.4 O 20-24 years: 18.7 I 25-34 years: 40.8 I 35-44 years: 36.2 I 45-64 years: 84.7 I 65 years and over: 54.7 The sample mean is x=. (Round to two decimal places as needed.) The sample standard deviation is s = (Round to two decimal places as needed.)
The sample mean amount of savings is $
QUEST A set of final examination grades in a calculus course was found to be normally distributed with a mean of 69 and a standard deviation of 9. The top 15% of the students taking the test scored will receive a grade of B. What is the cur score?
Determine whether the following graph can represent a variable with a nomal distribution. Explain your reasoning. If the graph appears to represent a normal distribution, estimate the mean and standard deviation. 10 15 20 25 30 Could the graph represent a variable with a normal distribution? Explain your reasoning. Select the correct choice below and, if necessary, fill in the answer boxes within your choice. O A. No, because the graph crosses the x-axis. O B. No, because the graph is skewed nght. O C. No, because the graph is skewed left. O D. Yes, the graph fulfills the properties of the normal distribution. The mean is approximately and the standard deviation is about- (Type whole numbers.) Clear all Final chec Help me solve this View an example Get more help -
The mean age of two people in a room is 20 years. A 50 year old person enters the room. What is the mean age of the 3 people in the room now 20 30 33.3 35 none of the above
The distribution of the number of hours that a random sample of people spend doing chores per week is shown in the pie chart. Use 32 as the midpoint for "30+ hours." Make a frequency distribution for the data. Then use the table to estimate the sample mean and the sample standard deviation of the data set. W Click the icon to view the pie chart. ..... 5-9 12 10-14 23 15-19 16 20-24 18 25-29 12 30+ 4 Find an approximation for the sample mean. x= 16.6 (Type an integer or decimal rounded to the nearest tenth as needed.) Find an approximation for the sample standard deviation. s= (Type an integer or decimal rounded to the nearest tenth as needed.)
The top 16 winning scores for NFL games are listed below. Find the mean score. Video Tutorial: How to find the mean on a TI-84 72 54 52 54 70 51 56 58 58 52 51 63 51 48 52 61 A. 54 B. 57.1 C. 63.2 D. 56.4
Using technology, find the range and standard deviation, round to one decimals place:The table below gives the number of hours spent watching TV last week by a sample of 24 children. 20 39 34 29 48 84 64 25 75 89 40 57 82 43 62 52 49 59 38 87 49 66 95 17 Range = 78 Standard Deviation = 22.6
What percentage of buyers paid between $14,500 and $16,000?
Find the mean, median, and mode of the set of values. Age (years) 12 Frequency 5 13 9 14 10 15 11 16 7 17 7 18 4

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