**Understanding Car Pricing Using Normal Distribution**When it comes to buying a car, not everyone pays the same price for the same model. The graph above illustrates a normal distribution of the amounts paid for a particular model of a new car. - **Key Information:** - **Mean (Average) Price:** $22,000 - **Standard Deviation:** $2,000Using the 68-95-99.7 Rule (Empirical Rule), we can determine the percentage of buyers who paid between $20,000 and $24,000.**Graph Details:**- The x-axis represents the price of the car model (in thousands), while the y-axis represents the number of car buyers.- The normal distribution curve is centered at the mean price of $22,000.- **Shaded Region (68%):** The area between $20,000 and $24,000 represents one standard deviation from the mean, capturing about 68% of the data.**Conclusion:** Using the 68-95-99.7 Rule, approximately 68% of buyers paid between $20,000 and $24,000 for the car. The percentage of buyers who paid between $20,000 and $24,000 is **68%**.

Mean = 22000 Standard deviation = 2000

Not everyone pays the same price for the same model of a car. The figure illustrates a normal distribution for the - 99.7%- 95% -68%- prices paid for a particular model of a new car. The mean is $22,000 and the standard deviation is $2000. Use the 68-95-99.7 Rule to find what percentage of buyers paid between $20,000 and $24,000. 24 26 28 Price of a Model of a New Car (Thousands) 16 18 20 22 The percentage of buyers who paid between $20,000 and $24,000 is %. Number of Car Buyers

Not everyone pays the same price for the same model of a car. The figure illustrates a normal distribution for the - 99.7%- 95% -68%- prices paid for a particular model of a new car. The mean is $22,000 and the standard deviation is $2000. Use the 68-95-99.7 Rule to find what percentage of buyers paid between $20,000 and $24,000. 24 26 28 Price of a Model of a New Car (Thousands) 16 18 20 22 The percentage of buyers who paid between $20,000 and $24,000 is %. Number of Car Buyers

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

The sample mean amount of savings is $
Determine whether the following graph can represent a variable with a nomal distribution. Explain your reasoning. If the graph appears to represent a normal distribution, estimate the mean and standard deviation. 10 15 20 25 30 Could the graph represent a variable with a normal distribution? Explain your reasoning. Select the correct choice below and, if necessary, fill in the answer boxes within your choice. O A. No, because the graph crosses the x-axis. O B. No, because the graph is skewed nght. O C. No, because the graph is skewed left. O D. Yes, the graph fulfills the properties of the normal distribution. The mean is approximately and the standard deviation is about- (Type whole numbers.) Clear all Final chec Help me solve this View an example Get more help -
A group of friends get together every Sunday for a little pick-up hockey. The age of the 20 regulars is shown below. 21 25 26 46 28 22 42 38 22 38 49 44 55 33 45 31 24 43 25 37 Find the mean, median, and mode for the distribution (ungrouped data). Which measure best describes these data? Explain. Group these data into six intervals and produce a frequency table. Determine the mean, and median for a new set of grouped data.
1. In a sentence or two, explain what a sampling distribution is. 2. In a sentence or two explain how the standard error of the mean is similar to the standard deviation.
Approximate the mean of the frequency distribution for the ages of the residents of a town. Age Frequency 0-9 31 10-19 27 20-29 14 30-39 20 40-49 22 50-59 43 60-69 46 70-79 11 80-89 7 What is the approximate mean age in years.
K A commuter tallied the time to work for 200 days and found that it resembled a normal curve. The mean time was 50 minutes, and the standard deviation was 2 minutes. For the 200-work-day experiment, find the percent of time commuting to work less than 44 minutes. 44 Minutes to Commute to Office 1 46 48 68%- 95% 99/7% 50
The distribution of the number of hours that a random sample of people spend doing chores per week is shown in the pie chart. Use 32 as the midpoint for "30+ hours." Make a frequency distribution for the data. Then use the table to estimate the sample mean and the sample standard deviation of the data set. Click the icon to view the pie chart. First construct the frequency distribution. Class Frequency, f 0-4 5-9 10-14 15-19 20-24 25-29 30+ Find an approximation for the sample mean. X= (Type an integer or decimal rounded to the nearest tenth as needed.) Find an approximation for the sample standard deviation. S= (Type an integer or decimal rounded to the nearest tenth as needed.) Weekly Chore Hours 0-4 hours (3 people) 5-9 hours (14 people) 10-14 hours (21 people) 15-19 hours (18 people) 20-24 hours (17 people) 25-29 hours (11 people) 30+ hours (7 people) - X -
The distribution of the number of hours that a random sample of people spend doing chores per week is shown in the pie chart. Use 32 as the midpoint for "30+ hours." Make a frequency distribution for the data. Then use the table to estimate the sample mean and the sample standard deviation of the data set. W Click the icon to view the pie chart. ..... 5-9 12 10-14 23 15-19 16 20-24 18 25-29 12 30+ 4 Find an approximation for the sample mean. x= 16.6 (Type an integer or decimal rounded to the nearest tenth as needed.) Find an approximation for the sample standard deviation. s= (Type an integer or decimal rounded to the nearest tenth as needed.)
Using technology, find the range and standard deviation, round to one decimals place:The table below gives the number of hours spent watching TV last week by a sample of 24 children. 20 39 34 29 48 84 64 25 75 89 40 57 82 43 62 52 49 59 38 87 49 66 95 17 Range = 78 Standard Deviation = 22.6
Find the mean, median, and mode of the set of values. Age (years) 12 Frequency 5 13 9 14 10 15 11 16 7 17 7 18 4
Find and interpret the z-score for North Carolina.
A survey of 30 people was conducted about how many siblings they had. A graph was created that showed the percentage of the survey group, which had each number of siblings. The "frequency" column in the table shows the number of responses that having a certain number of siblings received. Using appropriate and precise statistical terminology, describe the distribution and provide an explanation for the distribution being a certain way.