Normally, the amount of silver nitrate required to precipitate all of the chloride in the sample is found by a trial and error process. However, to speed up the experiment, assume a sample mass of 0.1431 g, and that sample contains approximately 55.0% chloride ion by mass. From these assumptions, calculate the volume of 0.100 M AgNO3(aq) that needs to be added to precipitate all of the chloride ion. Please answer in mL. (Note: You are calculating the exact amount required and not adding 5mL in excess. In the experiment, you'd be adding an additional 5mL in excess since the chloride value of the salt may exceed 55%. Pay attention to the sig. figs. in your calculation; keep three sig. figs. in the answer.)
Normally, the amount of silver nitrate required to precipitate all of the chloride in the sample is found by a trial and error process. However, to speed up the experiment, assume a sample mass of 0.1431 g, and that sample contains approximately 55.0% chloride ion by mass. From these assumptions, calculate the volume of 0.100 M AgNO3(aq) that needs to be added to precipitate all of the chloride ion. Please answer in mL.
(Note: You are calculating the exact amount required and not adding 5mL in excess. In the experiment, you'd be adding an additional 5mL in excess since the chloride value of the salt may exceed 55%. Pay attention to the sig. figs. in your calculation; keep three sig. figs. in the answer.)
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