Nominal Strength Analysis (Ultimate Strength Stage) Problem 3) Modified Problem 2.28 (page 59, McCormac and Brown, 10th Ed.) Change f'c to 5 ksi (a) Determine the depth of equivalent compression block, a = in

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Chapter9: Composite Construction
Section: Chapter Questions
Problem 9.1.3P
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Please answer problem 3. assume the sections have cracked and use the transferred area method to compute their flexural stresses for the loads or moments given 

Problem 2.13 (Ans. f. = 1762 psi; f, = 28,635 psi at the steel centroid)
30 k
2 k/ft (including beam weight)
n= 8
32 in.
36 in.
-10 ft-
20 ft
6 #9
30 ft
4 in.
-16 in.-
Transcribed Image Text:Problem 2.13 (Ans. f. = 1762 psi; f, = 28,635 psi at the steel centroid) 30 k 2 k/ft (including beam weight) n= 8 32 in. 36 in. -10 ft- 20 ft 6 #9 30 ft 4 in. -16 in.-
Nominal Strength Analysis (Ultimate Strength Stage)
Problem 3) Modified Problem 2.28 (page 59, McCormac and Brown, 10th Ed.)
Change f'. to 5 ksi
(a) Determine the depth of equivalent compression block, a =
in
(b) Nominal moment capacity, Mn =
ft*kip
Problem 4) Modified Problem 2.29 (page 59, McCormac and Brown, 10th Ed.)
Change beam width from 16 in. to 18 in.
(c) Find the centroid of the steel bars measured from top of the beam, d =
in
(d) Determine the depth of equivalent compression block, a =
in
(e) Nominal moment capacity, Mn =
ft*kip
Transcribed Image Text:Nominal Strength Analysis (Ultimate Strength Stage) Problem 3) Modified Problem 2.28 (page 59, McCormac and Brown, 10th Ed.) Change f'. to 5 ksi (a) Determine the depth of equivalent compression block, a = in (b) Nominal moment capacity, Mn = ft*kip Problem 4) Modified Problem 2.29 (page 59, McCormac and Brown, 10th Ed.) Change beam width from 16 in. to 18 in. (c) Find the centroid of the steel bars measured from top of the beam, d = in (d) Determine the depth of equivalent compression block, a = in (e) Nominal moment capacity, Mn = ft*kip
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ISBN:
9781337094740
Author:
Segui, William T.
Publisher:
Cengage Learning