node v₁: 3 (V₁-V₂) SA-3.1052 SA SA- 3(V₁-V3) 3052 SA- - 3V₁-3V3 V₁ V₂ 305 4V. +V₂+3V₂. 3052 -4V₁ + V₂ + 3V₂ = -150A (V₁-V₂) V₁-V₂ node v₂: -(V-V.). (v.₂-K). V+₂=0 102 40-52 3022 node V3: VI-V + VIOVI + VI SO V3-V₂ 105 403 -12 (V₂-v₁-3(V₂ -V₂ ) -4V₂ = 0 -1913 +3V₂ +12yY₁ = 0 2- 80. V₂-U 40 40 -12V3+12V₁-3V3+3V₂-4V3=0 =O =O (V₂-V₂) (V₂ -v₁) 40 - 80-V₂-V3- 40 U₂U INI VV 30 =O 240-3(V₂-V3-4(V₂-V₁) = 0 -3V₂ +3V3-4v₂ +4v₁ = -240 3V3-7V₂+4v₁ = -240
node v₁: 3 (V₁-V₂) SA-3.1052 SA SA- 3(V₁-V3) 3052 SA- - 3V₁-3V3 V₁ V₂ 305 4V. +V₂+3V₂. 3052 -4V₁ + V₂ + 3V₂ = -150A (V₁-V₂) V₁-V₂ node v₂: -(V-V.). (v.₂-K). V+₂=0 102 40-52 3022 node V3: VI-V + VIOVI + VI SO V3-V₂ 105 403 -12 (V₂-v₁-3(V₂ -V₂ ) -4V₂ = 0 -1913 +3V₂ +12yY₁ = 0 2- 80. V₂-U 40 40 -12V3+12V₁-3V3+3V₂-4V3=0 =O =O (V₂-V₂) (V₂ -v₁) 40 - 80-V₂-V3- 40 U₂U INI VV 30 =O 240-3(V₂-V3-4(V₂-V₁) = 0 -3V₂ +3V3-4v₂ +4v₁ = -240 3V3-7V₂+4v₁ = -240
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Question
Explain the steps that are happening in each one
Transcribed Image Text:node ₁:
3 (V₁-V₂)
SA-3.1052
SA-
●
3(V₁-V3)
3052
34-3V3
305
node v₂:
103
V3-V₁
SA-
5A - =
4V. +V₂+3V₂
3052
1052
2-
-4v₁ + V₂+3V₂ =-150A
(V₁-V₂)
40
3052 0
node V3:
V₁-V₂
V₂ = 0
305
(V₂-V₂>
140
V₁-V₂
V₂ 40
30V₂-V3
(U₂ - V₂) - 12 = 0
40-52
3022
-12 (V3-v₁-3(V₂-V₂ ) -4V₂=0
30 O
VI-VI + V1=0
V3-V₂
405
30.
-12V₂+12V,-3V3+3V₂-4V3=0
-19v3 +3V₂ +12V₁ = 0
4-U₂) - (U₂-V1)
30
V₂-V₁
30
80-V-V3 - V2-V
40
30
=O
240-3(V₂-V₂-4 (V₂-V₁) = 0
-3v₂ +3V3-4v₂ +4v₁ = -240
3V3-7 V₂ +4v₁ = -240
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