NMR spectroscopy **Transcription and Explanation for Educational Website**---**Figure**: Analysis of Spectroscopic Data---**a) \(^{13}\)C-NMR & IR Analysis**- **IR Spectroscopy**: - A broad signal is observed at approximately 3300 cm\(^{-1}\), which typically indicates the presence of an O-H or N-H group due to stretching vibrations.- **\(^{13}\)C-NMR Spectrum**: - **Chemical Shift (PPM) Assignments**: - **70-80 ppm**: A doublet (d) is observed, suggesting the presence of a carbon atom with neighboring hydrogen. - **~40 ppm**: A triplet (t) is observed. - **~30 ppm**: Another triplet (t) is observed.**b) \(^{13}\)C-NMR & MS Analysis**- **Mass Spectrometry**: - The molecular ion peak (M\(^+\)) is observed at 86, which provides information on the molecular weight of the compound.- **\(^{13}\)C-NMR Spectrum**: - **Chemical Shift (PPM) Assignments**: - **220 ppm**: A doublet (d) suggests the presence of carbonyl carbon. - **~80 ppm**: A doublet (d) similar to the previous spectrum. - **~40 ppm**: A triplet (t). - **~20 ppm**: Multiple signals include a triplet (t) and two quartets (q), indicating carbons bonded to other carbons and hydrogens.**Summary**:- The above spectra provide crucial information about the structural components of the compounds analyzed. The IR signal infers functional groups such as hydroxyl or amine, while NMR and MS provide insights into the carbon framework and molecular weight, respectively. Understanding these spectra is vital for interpreting molecular structures in organic chemistry.

1) The 13C NMR spectroscopy gives information about types of carbon atoms present in the molecule.2) Equivalent carbon atoms give only one signal while carbon from different environments gives different signals.3) IR spectroscopy gives information about functional groups present in the molecule.4) Mass spectrum gives molecular ion peak.a) IR : 3300 cm-1 broad signal indicates presence of hydroxyl group. (-OH).There are three signals in the 13C NMR spectra of given molecule.The multiplicity can be calculated by n+1 rule,where,1) 24 ppm, triplet, -CH2, 2) 31 ppm, triplet, -CH2, 3) 74 ppm, doublet, -O-CH, ,From the above information it is clear that there may be symmetry in the structure.The structure is shown below.b) mass peak at = 86,There are five signals in the 13C NMR spectrum,1) 11 ppm, quartet, -CH3,,2) 13 ppm, quartet, -CH3, ,3) 22 ppm, triplet, CH2, 4) 39 ppm, doublet, -CH, ,5) 204 ppm, doublet, -O=CH, aldehyde, From the above data the structure of compound is shown below.The structure of compounds a and b is shown in the above step:a) cyclopentanolb) 2-methylbutanal