Reactions of Ethers
Ethers (R-O-R’) are compounds formed by replacing hydrogen atoms of an alcohol (R-OH compound) or a phenol (C6H5OH) by an aryl/ acyl group (functional group after removing single hydrogen from an aromatic ring). In this section, reaction, preparation and behavior of ethers are discussed in the context of organic chemistry.
Epoxides
Epoxides are a special class of cyclic ethers which are an important functional group in organic chemistry and generate reactive centers due to their unusual high reactivity. Due to their high reactivity, epoxides are considered to be toxic and mutagenic.
Williamson Ether Synthesis
An organic reaction in which an organohalide and a deprotonated alcohol forms ether is known as Williamson ether synthesis. Alexander Williamson developed the Williamson ether synthesis in 1850. The formation of ether in this synthesis is an SN2 reaction.
Can you assist me in identifying what I am doing wrong in this reaction? Thank you.
Original Question:
Give the products expected from the following reactions.
![**Hexanoyl Chloride and Piperidine Reaction**
**Chemical Equation:**
\[ \text{CH}_3\text{(CH}_2)_4\text{C} \equiv \text{O} \_\_\_\text{Cl} + \text{Piperidine} \]
- **Reactants:**
- **Hexanoyl Chloride** \(\text{CH}_3\text{(CH}_2)_4\text{C} \equiv \text{O} \_\_\_\text{Cl}\)
- **Piperidine**
**Instructions for Drawing the Molecule:**
- Use the canvas to select atoms and bonds from the toolbar.
- Ensure charges are included where necessary.
**Molecular Structure Diagram:**
- The structure shows a cyclohexyl ring (piperidine) attached via a carbonyl group to a hexyl chain ending with a methyl group (\(\text{CH}_3\)).
**Toolbar Elements for Drawing:**
- **H (Hydrogen)**
- **C (Carbon)**
- **N (Nitrogen)**
- **O (Oxygen)**
- **S (Sulfur)**
- **Cl (Chlorine)**
- **Br (Bromine)**
- **I (Iodine)**
- **P (Phosphorus)**
- **F (Fluorine)**
Utilize these tools for constructing accurate molecular representations for educational purposes.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb041252e-6a65-4a9d-bb85-93f64c65df81%2F70ee5f0b-a76c-4d81-9845-238be43afe43%2F9zvwfj9_processed.png&w=3840&q=75)
Trending now
This is a popular solution!
Step by step
Solved in 2 steps with 2 images
