Newton's law of universal gravitation strictly applies to perfectly spherical bodies. Many celestial bodies, like the Sun and Earth, are not perfect spheres. This has a measureable effect on the trajectories of orbiting satellites. Restricting attention to equatorial orbits, the gravity law can be corrected in a simple way to account for the Sun's imperfect shape. Fg where G = 6.67 × 10-¹¹ N-m²/kg² is the universal gravitation constant, M = 1.99 × 1030 kg is the mass of the Sun, m is the mass of the orbiting body, R = 6.96 × 105 km is the mean radius of the Sun, and J₂ = 2.91 × 10-6 is the solar quadrupole moment, a dimensionless parameter that characterizes the Sun's slightly aspherical shape. GMm p2 1+ W = 3J2R² 2r² r What is the extra work W done by the correction term in the gravity law when a small comet moves from aphelion to perihelion along an equatorial orbit? The comet's perihelion, or the distance of closest approach to the Sun, is rp = 1.85 AU (astronomical units). The aphelion, or its largest distance from the Sun, is ra = 9.33 AU. The comet's mass is m = 1.42 x 106 kg, and it orbits the Sun once every 13.7 years. See the hint for help with conversion from astronomical units to meters. J

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Newton's law of universal gravitation strictly applies to perfectly spherical bodies. Many celestial bodies, like the Sun and Earth,
are not perfect spheres. This has a measureable effect on the trajectories of orbiting satellites. Restricting attention to equatorial
orbits, the gravity law can be corrected in a simple way to account for the Sun's imperfect shape.
==
GMm
p²
W =
(1 + 3/2R² ) ;
2r²
where G = 6.67 × 10-¹¹ N·m²/kg² is the universal gravitation constant, M = 1.99 × 1030 kg is the mass of the Sun, m is the
mass of the orbiting body, R = 6.96 × 105 km is the mean radius of the Sun, and J₂ = 2.91 × 10−6 is the solar quadrupole
moment, a dimensionless parameter that characterizes the Sun's slightly aspherical shape.
What is the extra work W done by the correction term in the gravity law when a small comet moves from aphelion to perihelion
along an equatorial orbit? The comet's perihelion, or the distance of closest approach to the Sun, is
rp = 1.85 AU (astronomical units). The aphelion, or its largest distance from the Sun, is ra = 9.33 AU. The comet's mass is
m = 1.42 × 106 kg, and it orbits the Sun once every 13.7 years. See the hint for help with conversion from astronomical units
to meters.
Transcribed Image Text:Newton's law of universal gravitation strictly applies to perfectly spherical bodies. Many celestial bodies, like the Sun and Earth, are not perfect spheres. This has a measureable effect on the trajectories of orbiting satellites. Restricting attention to equatorial orbits, the gravity law can be corrected in a simple way to account for the Sun's imperfect shape. == GMm p² W = (1 + 3/2R² ) ; 2r² where G = 6.67 × 10-¹¹ N·m²/kg² is the universal gravitation constant, M = 1.99 × 1030 kg is the mass of the Sun, m is the mass of the orbiting body, R = 6.96 × 105 km is the mean radius of the Sun, and J₂ = 2.91 × 10−6 is the solar quadrupole moment, a dimensionless parameter that characterizes the Sun's slightly aspherical shape. What is the extra work W done by the correction term in the gravity law when a small comet moves from aphelion to perihelion along an equatorial orbit? The comet's perihelion, or the distance of closest approach to the Sun, is rp = 1.85 AU (astronomical units). The aphelion, or its largest distance from the Sun, is ra = 9.33 AU. The comet's mass is m = 1.42 × 106 kg, and it orbits the Sun once every 13.7 years. See the hint for help with conversion from astronomical units to meters.
Expert Solution
Step 1

Any two point masses in the universe attract each other with gravitational force that is proportional to their masses and inversely proportional to the distance squared between them.

Here given that,

Universal gravitational constant G=6.67×10-11 N.m2/kg2

The mass of the sun is M=1.99×1030 kgMean radius of the sun R=6.96×105 kmThe solar quadrupole moment J2=2.91×10-6

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