A faraway, imaginary planet has one moon which has a nearly circular periodic orbit. Let the distance between the surface of the imaginary planet and the center of the moon be 2.075 × 10° km and the planet has a radius of 4125 km and a mass of 6.55 × 1022 kg, how many days will it take the moon to travel one time around the imaginary planet. The gravitational constant is 6.67 × 10-11 N · m²/kg². T = days

icon
Related questions
Question
A faraway, imaginary planet has one moon which has a nearly circular periodic orbit. Let the distance between the surface of the imaginary planet and the center of the moon be \(2.075 \times 10^5\) km, and the planet has a radius of 4125 km and a mass of \(6.55 \times 10^{22}\) kg. How many days will it take the moon to travel one time around the imaginary planet? The gravitational constant is \(6.67 \times 10^{-11} \text{ N} \cdot \text{m}^2/\text{kg}^2\).

\[
T = \underline{\hspace{6cm}} \text{ days}
\]
Transcribed Image Text:A faraway, imaginary planet has one moon which has a nearly circular periodic orbit. Let the distance between the surface of the imaginary planet and the center of the moon be \(2.075 \times 10^5\) km, and the planet has a radius of 4125 km and a mass of \(6.55 \times 10^{22}\) kg. How many days will it take the moon to travel one time around the imaginary planet? The gravitational constant is \(6.67 \times 10^{-11} \text{ N} \cdot \text{m}^2/\text{kg}^2\). \[ T = \underline{\hspace{6cm}} \text{ days} \]
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps with 2 images

Blurred answer