Scientists have discovered a distant
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Scientists have discovered a distant planet with a mass of 6.4x1023 kg. The planet has a small moon that orbits with a period of 6 hours and 26 minutes. Using only this information (and the value of G) to calculate the radius of the moon's orbit (in units of 106 m).
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- Assume the earth's mass is 85.47 x 1025 kg, and radius is 51.93 x 103 miles, what would be the gravitational acceleration on such an planet in unit of m/s2? Use G=6.67x 10 -11 Nm2/kg2.Planet Z-1 has a mass equal to one-third that of the Earth and a radius equal to one- third that of the Earth. With g representing the acceleration of gravity on the surface of Earth, the acceleration due to gravity on the surface of Z-1 is g/3 3g 6g g/9 8gScientists want to place a 4 × 103 kg satellite in orbit around Mars. They plan to have the satellite orbit at a speed of 2330 m/s in a perfectly circular orbit. Here is some information that may help solve this problem: mmars = 6.4191 x 1023 kgrmars = 3.397 x 106 mG = 6.67428 x 10-11 N-m2/kg2 1.)What should the speed of the orbit be, if we want the satellite to take 8 times longer to complete one full revolution of its orbit?
- The International Space Station (ISS) is a space station orbiting the earth above the ground. If the radius of the earth is 3,958.8 miles, mass of earth is 5.972 x 10 24 kg, the period of the ISS at the orbit around the earth is 10.934 hours, can you calculate what is the distance from the ISS to the surface of the earth, in unit of miles? Use G=6.674 x 10 -11 Nm2/kg2. Write your answer in pure numbers, for example, 4567.8. Please keep at least on digit after the decimal point.During a solar eclipse, the Moon is positioned directly between Earth and the Sun. The masses of the Sun, Earth, and the Moon are 1.99×10^30 kg, 5.98×10^24 kg, and 7.36×10^22 kg, respectively. The Moon's mean distance from Earth is 3.84×10^8 m, and Earth's mean distance from the Sun is 1.50×10^11 m. The gravitational constant is G=6.67×10^−11 N·m2/kg^2. Find the magnitude F of the net gravitational force acting on the Moon during the solar eclipse due to both Earth and the Sun.29. Consider Planet X whose mass and radius are 9.05 x 1025 [kg] and 5.95 x 104 [m], respectively. If the weight of the object on the surface of the Earth is 2940 [N], what is its weight at height 750 [m] from the surface of the Planet X? Note: The gravitational constant is G = : 6.6743 x 10-11 m3 A. 3.70 × 108 [N] C. 4.99 x 108 [N] B. 4.88 x 108 [N] D. 5.12 x 108 [N] Lkg
- The Lunar reconnaissance orbiter (LRO) is currently in orbit around the moon on an exploration mission to map its surface. If it has a mass of 1820 kg and is orbiting at an elevation of 65.0 km from the surface, what is the gravitational force acting on the LRO due to the moon? The moon has a mass of 7.348 x 1022 kg and a radius of 1738 km. {G = 6.674 x 10-11 N m2/kg?} r = 1,803 km 1738 km I m, Norbiter = 1,820 kg mmoon 7.348 × 102² kg 65.0 kmA new planet named Vulcan has been discovered. Vulcan is a rather large planet with a radius twice that of Earth and a mass three times that of Earth. An astronaut has a mass of 60.0 kg and weighs about 132 lbs. on Earth. If the astronaut is on the planet Vulcan, what is her weight? The following numerical values may be helpful in this question. G = 6.67 ∙10-11 N∙m2/ kg2 Earth’s mass = 5.98 · 1024 kilograms g = 9.80 m/sec2 1 kilometer = 1000 metersThe mean distance of an asteroid from the Sun is 1.74 times that of Earth from the Sun. From Kepler's law of periods, calculate the number of years required for the asteroid to make one revolution around the Sun.
- Help me to solve this problem step by step and give answer as a 3 significant figuresAssume the earth's mass is 23.335 x 1025 kg, and radius is 76.394 x 103 miles, what would be the gravitational acceleration on such an planet in unit of m/s2? Use G=6.67x 10 -11 Nm2/kg2.The International Space Station (ISS) is a space station orbiting the earth above the ground. If the radius of the earth is 3,958.8 miles, mass of earth is 5.972 x 10 24 kg, the period of the ISS at the orbit around the earth is 9.16 hours, can you calculate what is the distance from the ISS to the surface of the earth, in unit of miles? Use G=6.674 x 10 -11 Nm2/kg2. Write your answer in pure numbers, for example, 4567.8. Please keep at least on digit after the decimal point.